Cards (6)

  • The equilibrium concentration of H+
    • dissociation of H+ and A- ions in equal amounts
    • at equilibrium, [H+] = [A-]
  • The equilibrium concentration of HA
    • only a very small proportion of HA dissociate
    • [HA] at equilibrium = [HA] undissociated
  • With the two assumptions
    • Ka = [H+]^2/[HA]
  • [H+] = root(Ka x [HA])
  • Approximation for equilibrium [H+] ~ [A-]
    • this breaks down for very weak acids or very dilute solutions
  • Approximation for [HA] equilibrium ~ [HA] undissociated
    • this breaks down for stronger acids and concentrated solutions