24.4 Ligand substitution and precipitation

Cards (17)

  • Ligand substitution is a reversible reaction of a complex ion in which one ligand is replaced by another ligand
  • Cu2+ hexaaqua complexes react with excess aqueous ammonia by ligand substitution
    • four water molecules are replaced by four NH3 ligands
    • Colour changes from light blue to dark blue
  • Cu2+ hexaaqua complexes react with an excess of chloride ions by ligand substitution
    • six water molecules are replaced by four Cl- ligands
    • Colour changes from light blue to yellow
  • Cr3+ hexaaqua complexes react with excess aqueous ammonia by ligand substitution
    • six water molecules are replaced by six NH3
    • Colour changes from violet to purple
  • Haemoglobin in red blood cells contain four protein chains
    • each protein chain has a planar haem molecule within its structure
    • the Fe2+ metal ion in haem bonds to a protein chain and water
    • Water can exchange readily with oxygen
  • Carbon monoxide can also bond to the Fe2+ ion in haemoglobin by ligand substitution with an oxygen, the bond is so strong the process is irreversible
  • A precipitation reaction is a reaction between ions in two aqueous solutions to form an insoluble ionic solid
  • Aqueous transition metal ions react with NaOH and NH3 to form precipitates of the metal hydroxide -> some of these dissolve in excess to form complex ions in solution
  • Cu2+ + 2OH- -> Cu(OH)2
    light blue -> blue precipitate
  • Fe2+ + 2OH- -> Fe(OH)2
    pale green -> green precipitate
  • The green precipitate of Fe(OH)2 turns brown at the surface because the iron(II) is oxidised to iron(III) with contact to air
  • Fe3+ + 3OH- -> Fe(OH)3
    yellow -> orange brown precipitate
  • Mn2+ + 2OH- -> MN(OH)2
    pale pink -> light brown precipitate
  • Cr3+ + 3OH- -> Cr(OH)3
    violet -> green precipitate
  • The hydroxide of Cr3+ dissolves in excess NaOH
    Cr(OH)3 -> [Cr(OH)6]3-
    green precipitate -> dark green
  • The hydroxide of Cr3+ dissolves in excess NH3
    Cr(OH)3 -> [Cr(NH3)6]3+
    green precipitate -> purple
  • The hydroxide of Cu2+ dissolves in excess NH3
    Cu(OH)2 -> [Cu(NH3)4(H20)2]2+
    blue precipitate -> dark blue