Elimination

• Elimination of alcohols 

  Conditions required

  • Hot temperature
  • Concentrated H2SO4 catalyst

  The lone pairs on oxygen on the alcohol go to the slightly positive hydrogen. Bonding that hydrogen to the oxygen.

  A positive charge is on the oxygen so the bond between carbon and oxygen goes to it

  While a bond between C and H on adjacent carbon forms a double bond forming an alkene

  H+ reforms since a catalyst is used
• Halogenalkanes to alkenes

  Halogenalkanes go through elimination reaction to form Alkenes

  • With the OH- acting as a base
  • Hot and ethanoic conditions
• Haloalkane to alkene

  The lone pair on the OH- would attack the hydrogen on the carbon next to the halogen and take it. The bond from that hydrogen goes to form a double bond. There's too many things bonded on the carbon so a bond from the carbon goes to the halogen
• Elimination of alcohols

  The H+ comes from a H2SO4 catalyst. The lone pair on the Oxygen in the OH goes to the H+. This makes the oxygen positive so a bond from the carbon goes to the oxygen. Hydrogen from an adjacent carbon has it bond turned to a double bond