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chemical changes
electrolysis
electrolysis of molten compound
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Cards (21)
Electrolysis on
MOLTEN
Sodium Chloride will always form
sodium
&
chlorine
aqueous
sodium chloride does not.
MOLTEN SODIUM CHLORIDE electrolyte:
The
IONS
involve is
Na+
&
Cl-
This means the
electrolyte
has these ions floating around in it.
When the circuit is turned on &
electricity
flows,
the Na+ ions get attracted to the
CATHODE
& the Cl- ions get attracted to the
ANODE.
When they reach the anodes, both sets of ions
TRANSFER
ELECTRONS
& turn into
ATOMS
of
ELEMENTS.
Na+
IONS
turn into Na
ATOMS
, while Cl-
ions
turn into Cl
ATOMS.
To represent these processes, you can write their
HALF
EQUATIONS.
ELECTROLYSIS HALF EQUATIONS - Step 1:
Write the ION of the element on the
LEFT
& the ATOM of the element on the
RIGHT.
ELECTROLYSIS HALF EQUATIONS - Step 2:
Check if any of the elements are
DIATOMIC
(exist as two atoms).
Here is a list of ALL the DIATOMIC elements you need to know.
Chlorine is part of the list so it needs to be changed to Cl2.
Diatomic elements:
Hydrogen
(H2)
Nitrogen
(N2)
Oxygen
(O2)
Group
7
elements:
F2
Cl2
Br2
I2
ELECTROLYSIS HALF EQUATIONS - Step 3:
BALANCE
the equation to make sure you have the same numbers on the left & right.
ELECTROLYSIS HALF EQUATIONS - Step 4:
Add
ELECTRONS
to make the charges in the equation balanced.
For ANODES, electrons go on the
RIGHT.
For CATHODES, electrons go on the
LEFT.
Metals
MORE
reactive than
CARBON
can
NOT
be extracted by
REDUCTION
.
These metals need
ELECTROLYSIS
for extraction.
A large amount of energy is required as the metal ore needs to be
MELTED
to become
MOLTEN
&
ELECTRICITY
is needed for the electrolysis.
This makes the process
EXPENSIVE
.
There's usually more than one anode submerged in the electrolyte, & the cathode lines the
INSIDE
of the container.
Both electrodes are made of
GRAPHITE
.
The ions present in the liquid include
POSITIVE
ALUMINIUM
IONS
(Al3+) &
NEGATIVE
OXYGEN
IONS
(O2-).
When current flows through the set up, the
ALUMINIUM
ions are attracted to the
CATHODE
& the
OXYGEN
ions are attracted to the
ANODE
.
To find the half equation:
Write
ions
to
atoms
check for
diatomic
atoms
balance
add
electrons
The Aluminum is produced as a
MOLTEN
LIQUID
, which flows to the bottom of the container due to the
HIGH
TEMPERATURE.
The Oxygen is produced as
BUBBLES
, which float to the top of the liquid.
During electrolysis of a molten mixture of aluminum oxide & cryolite the GRAPHITE ANODES need to be REPLACED REGULARLY.
Because at
high
temp. oxygen reacts with
carbon.
So the positive electrode
wear
away
to form
carbon
dioxide.
Magnesium ions attracted to the
electrode
, so magnesium ions gain 2 electrons.
Aluminum ions are positive & are attracted to the negative electrode (cathode), where they
gain
elections.
Al3+
+
3e-
->
Al
Explain how carbon dioxide at the positive electrodes during electrolysis:
The positive electrode (anodes) are made of
carbon
/
graphite
, oxygen is
produced
at anode, which
reacts
with the
anodes.
Number of atoms =
10
zinc ions are
positive
, so they move towards the
negative
electrode
and
opposite
charges
attract.
Cryolite
:
A
mineral
that
lowers
melting
point.
To turn aluminum oxide
molten
:
Aluminum oxide is found within
solid
bauxite
ore
on earth & can be extracted using
electrolysis
.
Purify
the aluminum oxide from the bauxite ore, mined from the ground.
Mix
the aluminum oxide with
cryolite
to
lower
the
melting
point.
So
LESS
ENERGY
is needed to melt it, making the process
CHEAPER
.
Melt it to
molten
aluminum oxide.
Electrolysis
of
aluminum
oxide
:
The
oxygen
2-
ions
are
attracted
to the
anode
.
They’ll transfer their
two
extra
electrons
to the anode &
discharged
to oxygen
atoms.
Each
pair
of oxygen can combine an oxygen
molecule
&
float
into the
air.
Electrons
pass
through the
wire
to the
negative
cathode.
It
attract
the
positive
ions
in the
electrolyte
&
donate
electrons
to them.
The
positive
ions
will slowly
pool
in the
bottom
of the
beaker
as
molten
aluminum
metal.
Electrolysis of aluminum oxide:
2Al2O3
(l) ➔
4Al
(l) +
3O2
(g)
At the anode:
O2-
->
O2
+
2e-
But since oxygen forms
diatomic
molecules
, we need 2 oxygen ions at the left & 4 electrons will be released in total.
At the anode:
2O2-
->
O2
+
4e-
(
oxidised
)
At the cathode:
Al3+
+
3e-
->
Al
(
reduced
)