When P4O10 is added to an alkaline solution it first reacts with water to form phosphoric acid which then reacts with the base to form the following equations if there is an excess of base.
H3PO4 + NaOH(aq) --> NaH2PO4 (aq) + H2O (l)
NaH2PO4 + NaOH (aq) --> Na2HPO4 (aq) + H2O (l)
Na2HPO4 + NaOH(aq) ---> Na3PO4(aq) + H2O (l)
Overall equation is:
H3PO4 + 3NaOH --> Na3PO4 (aq) + 3H2O
The reaction starting with P4O10 as the reactant would look like:
P4O10 + 12NaOH --> 4Na3PO4 (aq) + 6H2O
Acidic oxides pt2
Sulfur oxides reacts with NaOH to form:
SO2 (aq) + NaOH (aq) --> NaHSO3 (aq)
Then the sodium hydrogen sulfate reacts with NaOH to form sodium sulfate
NaHSO3 (aq) + NaOH (aq) --> Na2SO3 (aq) +H2O (l)
Overall reaction:
SO2 (aq) + 2NaOH (aq) --> Na2SO3 (aq) + H2O (l)
Due to some oxides being bases and others acids they can react in an acid-base reaction e.g.