Calculating the pH of 0.025 moldm-3 of CH3COOH acid with 4.75 pKa?
1: Ka= 10^-4.75= 1.78x10^-5 moldm-3.
2: Calculate [H+] from the Ka expression.
[H+]^2= Ka x [HA]. 1.78x10^-5 x 0.025= 4.45x10^-7
[H+]= Square root of 4n45x10^-7= 6.67x10^-4.
3: Calculate pH -log10[H+]= 3.18