amount of substance

Cards (12)

  • relative atomic mass equation
    sum of(mass×abundance of each isotope)÷total abundancesum\ of\left(mass\times abundance\ of\ each\ isotope\right)\div total\ abundance
  • the mole
    the amount of substance that contains as many particles as there are in exactly 12g of carbon-12
  • the ideal gas equation
    pV=nRT
  • empirical formula
    the simplest whole number ratio of atoms of each element present in a molecule
  • molecular formula
    the actual number of atoms of each element present in a molecule
  • how to make a standard solution
    • record the mass of a weighing boat and solid
    • tip the solid into a beaker and record the mass of the weighing boat
    • determine the mass of solid used by calculating the difference
    • dissolve the solid in deionised water
    • using a funnel, transfer into a volumetric flask, include washings
    • make up to the graduated line by carefully adding deonised water making sure the meniscus sits on the line
    • stopper the flask and invert to mix the contents thoroughly
  • to find the concentration of a solution of a base
    • fill a burette with a standard solution of the acid
    • pipette a known volume of base into conical flask
    • add a few drops of indicator to the base in the flask
    • add the solution of the acid from the burette until the indicator just changes colour. this is known as the end point
    • record the volume of acid added: record your burette readings to the nearest 0.05cm3
    • perform a rough titration and then sufficient accurate ones until the titres are concordant
    • calculate the mean titre from the concordant titres- to 2d.p.
  • percentage error
    uncertaintyvalue×100\frac{uncertainty}{value}\times100
  • to calculate the number of moles of water of crystallisation
    • need to know the masses of the hydrated and anhydrous salts
    • mass of water= mass hydrated salt- mass anhydrous salt
    • work out the number of moles of anhydrous salt and of water
    • find the simplest whole number ratio
  • percentage yield
    actual yieldtheoretical yield×100\frac{actual\ yield}{theoretical\ yield}\times100
  • reasons for a low percentage yield
    • incomplete reaction/ reversible reaction
    • side reactions may occur
    • loss of product during transfer or purification steps
    • impurities in the reactants
  • atom economy
    Mr desiredMr total×100\frac{Mr\ desired}{Mr\ total}\times100