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Chemistry
amount of substance
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Cards (12)
relative atomic mass equation
s
u
m
o
f
(
m
a
s
s
×
a
b
u
n
d
a
n
c
e
o
f
e
a
c
h
i
s
o
t
o
p
e
)
÷
t
o
t
a
l
a
b
u
n
d
a
n
c
e
sum\ of\left(mass\times abundance\ of\ each\ isotope\right)\div total\ abundance
s
u
m
o
f
(
ma
ss
×
ab
u
n
d
an
ce
o
f
e
a
c
h
i
so
t
o
p
e
)
÷
t
o
t
a
l
ab
u
n
d
an
ce
the mole
the amount of
substance
that contains
as
many
particles
as there are in exactly
12g
of
carbon-12
the ideal gas equation
pV=nRT
empirical formula
the
simplest
whole number
ratio
of
atoms
of each
element
present in a molecule
molecular formula
the
actual
number of
atoms
of each
element
present in a molecule
how to make a standard solution
record the
mass
of a weighing boat and
solid
tip the solid into a beaker and record the mass of the
weighing
boat
determine the mass of solid used by
calculating
the
difference
dissolve the solid in
deionised water
using a
funnel
, transfer into a
volumetric flask
, include
washings
make up to the
graduated
line
by carefully adding
deonised
water making sure the
meniscus
sits on the
line
stopper
the flask and
invert
to mix the contents thoroughly
to find the
concentration
of a solution of a
base
fill a
burette
with a
standard solution
of the
acid
pipette
a known volume of
base
into conical flask
add a few drops of
indicator
to the base in the flask
add the solution of the acid from the
burette
until the indicator
just
changes colour. this is known as the
end point
record the volume of acid added: record your burette readings to the nearest
0.05cm3
perform a
rough
titration
and then sufficient accurate ones until the titres are
concordant
calculate the
mean titre
from the concordant titres- to
2d.p.
percentage error
u
n
c
e
r
t
a
i
n
t
y
v
a
l
u
e
×
100
\frac{uncertainty}{value}\times100
v
a
l
u
e
u
n
cer
t
ain
t
y
×
100
to calculate the number of moles of water of crystallisation
need to know the
masses
of the
hydrated
and
anhydrous
salts
mass of water= mass
hydrated
salt- mass
anhydrous
salt
work out the number of
moles
of anhydrous salt and of water
find the
simplest whole number ratio
percentage yield
a
c
t
u
a
l
y
i
e
l
d
t
h
e
o
r
e
t
i
c
a
l
y
i
e
l
d
×
100
\frac{actual\ yield}{theoretical\ yield}\times100
t
h
eore
t
i
c
a
l
y
i
e
l
d
a
c
t
u
a
l
y
i
e
l
d
×
100
reasons for a low
percentage yield
incomplete reaction
/
reversible reaction
side
reactions may occur
loss of product during
transfer
or
purification
steps
impurities
in the
reactants
atom economy
M
r
d
e
s
i
r
e
d
M
r
t
o
t
a
l
×
100
\frac{Mr\ desired}{Mr\ total}\times100
M
r
t
o
t
a
l
M
r
d
es
i
re
d
×
100