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Chemistry
acids and bases
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Created by
lily newton
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Cards (13)
strong acid
completely
dissociates in solution
weak acid
partially
dissociates in soltion
pH equation
-
log
10
[
H
+
]
\log_{10}\left[H+\right]
lo
g
10
[
H
+
]
[H+] equation
10
−
p
H
^{-pH}
−
p
H
when pH changes by 1...
[H+] changes by a factor of
10
equation for a weak acid
K
a
=
Ka=
K
a
=
[
H
+
]
[
A
−
]
[
H
A
]
\ \frac{\left[H+\right]\left[A-\right]}{\left[HA\right]}
[
H
A
]
[
H
+
]
[
A
−
]
pKa equation
p
K
a
=
pKa=
p
K
a
=
−
log
10
K
a
-\log_{10}Ka
−
lo
g
10
K
a
in a weak acid we can assume
[H+]=[A-] therefore,
[
H
+
]
2
[
H
A
]
\frac{\left[H+\right]^2}{\left[HA\right]}
[
H
A
]
[
H
+
]
2
so, [H+]=
K
a
[
H
A
]
\sqrt{Ka\left[HA\right]}
K
a
[
H
A
]
convert pKa into Ka
Ka=
1
0
−
p
K
a
10^{-pKa}
1
0
−
p
K
a
ionic product of water
Kw
Kw equation
[
H+
][
OH-
]
at 298K, Kw equals
1
×
1
0
−
14
1\times10^{-14}
1
×
1
0
−
14
buffer solution
solution that maintains an
approximately
constant
pH on addition of
small
amounts
of acid or base