Atomic structure

Cards (42)

  • State the block in the Periodic Table in which sulphur is placed and explain your answer. (1)
    P block (1)
    Highest energy electrons occupy a p-orbital (2)
  • Explain how ions are detected and relative abundance is mesasured in a ToF mass spectrometer (2)
    Ions hit the detector AND gains an electron, creating a current (1)
    The relative abundance is proportional to the current (2)
  • Describe how ionisation is achieved in a mass spectrometer. Explain how the principle of ToF allows ions to be distinguished from each other. (4)
    Ionisation - bombardment of HIGH ENERGY ELECTRONS (1). Causes an electron to be knocked off the ion leaving a 1+ ion(2)

    ToF - the LOWER the m/z value (or mass)(3), the FASTER the ion reaches the detector (4)
  • Describe the stages of electrospray ionisation (4)
    Sample is dissolved in a volatile solvent and injected through a fine hypodermic needle (1)
    The tip of the needle is attached to the positive side of a power supply and so has a high voltage (2)
    As spray emerges from end of the needle, the particles gain a proton from the solvent(3)
    The solvent evaporates leaving 1+ ions that move towards a negative plate (4)
    Adds a hydrogen ion so the Mr increases by 1
  • What does the mass spectrometer determine? (1)
    M/z value and relative abundance
  • Why is the TOF mass spectrometer kept under a high vacuum? (1)
    To prevent the ions that are produced colliding with molecules from the air
  • Why is electron impact only used for elements and low Mr compounds? (1)
    Can cause larger organic molecules to fragment
  • What are the smaller peaks that cluster around the molecular ion peak? (2)
    Due to different isotopes (1)
    These isotopes have different masses and so different m/z values (2)
  • What does the main peak on a mass spectra show? (2)
    Molecular ion peak (1)
    Peak of the greatest m/z ratio (2)
    Represents the m/z value of the molecule analysed
  • What does a mass spectrum show? (2)
    M/z ratio (1)
    Abundance of each ion that reaches the detector (2)
    If ions have a 1+ charge, then the m/z value equals the mass of each ion
  • What happens in flight tube/ion drift in mass spectrometry? (2)
    Positive ions travel through a hole in the negatively charged plate and travels along the flight tube (1)
    The ToF of each particle through the flight tube depends on its mass (2)
  • What is the detection stage in mass spectrometry? (3)
    Ions hit a negatively charged electric plate (1)
    When hit, the positive ions are discharged by gaining electrons from the plate. This generates a movement of electrons and an electric current is produced and measured (2)
    Size of the current gives a measure of number of ions hitting the electric plate. (3)
    (The relative abundance is proportional to the current)
  • What happens during the acceleration stage in mass spectrometry? (2)
    The ions are attracted to a negatively charged plate and accelerate to it
    so all ions have the same kinetic energy
    so the velocity of each particle depends on its mass
  • Define orbital (1)

    a region of space around the nucleus where there is a high probability of finding an electron
  • Explain why different ions take different times to travel through the flight tube (2)
    time of flight depends on mass of ions (1)
    lighter ions travel faster (2)
  • Define relative atomic mass (2)
    The average mass of an atom of an element (1) compared to 1/12 of the mass of an atom of carbon 12 (2)
  • Describe electron impact (3)
    Sample is vaporised (1)
    High energy electrons are fired at it from an electron gun (2)
    This knocks off one electron from each particle forming a 1+ ion (3)
    eg. Ti (g) ———> Ti+ (g) + e-
  • Define atomic orbitals
    A region around the nucleus that can hold up to 2 electrons with opposite spins
  • Define ionisation energy (1)
    The energy required to remove a mole of electrons from a mole of atoms in the gaseous state (1)
  • What is the effect on the ionisation energy if the shielding is greater?
    - means there's more shells in the atom so there is a greater distance between the nucleus and the outermost electron
    - there's a weaker electrostatic attraction on the outermost electron
    - so less energy is needed to remove the outermost electron
    - so the ionisation energy is lower
  • What is the effect on the ionisation energy if the nuclear charge is greater?
    - more protons in the nucleus
    - bigger nuclear charge
    - stronger electrostatic attraction between outermost electron and nucleus
    - more energy is needed to remove the outermost electron
    - higher first ionisation energy
  • Trends in first ionisation energy across a period and down the group
    - across the period - ionisation energy increases
    - down a group - ionisation energy decreases
  • Explain the general trend of ionisation energy across a period
    - outermost electrons are in the same shell so the shielding remains similar
    - more protons in the nucleus so the nuclear charge increases
    - electrostatic attraction on the outermost electron increases
    - more energy is needed to remove the outermost electron
    - so first ionisation energy increases
  • Explain the general trend of ionisation energy down a group
    - more shells so outermost electron is further form the nucleus
    - so more shielding from inner electrons
    - although nuclear charge increases, this is outweighed by greater distance and shielding
    - so weaker electrostatic attraction on outermost electron
    - less energy needed to remove outermost electron
    - so first ionisation energy decreases
  • Explain the drop in 1st ionisation energy between group 2 and 3
    Eg. Mg - ends in 3s2
    Al ends in 3p1
    - The electron in the 3p sub-shell is of a higher energy than 3s
    - the electron in the 3p sub-shell is slightly further from the nucleus and experiences slightly more shielding than the 3s electrons
    - so slightly less energy is required to remove it
  • Explain the drop in 1st ionisation energy between group 5 and 6
    Eg. Phosphorus - ends in 3p3
    Sulphur ends in 3p4
    - P has no paired electrons while S has a pair of electrons in one of of the 3p orbitals
    - these paired electrons repel each other so less energy is needed to remove the paired electron than the unpaired
  • Explain the general trend in ionisation energy graphs
    - general trend increases
    - successive ionisation energies increase, as electrons are being removed from an increasingly positive ion
    - so electrostatic attraction between the nucleus and remaining outermost electron increases
  • Explain the big jump in successive ionisation energy graphs
    - a large increase in ionisation energy represents a change of shell
    - so when an electron is being removed from a lower shell, which is closer to the nucleus, the electrostatic attraction is much stronger so ionisation energy suddenly becomes much larger
    - the shell loser to the nucleus experiences less shielding
  • Explain why the ionisation energy of every element is endothermic (1)
    - energy is needed to overcome the attraction between the negative electron and positive nucleus (1)
  • Explain how the abundance of an isotope in a sample of Rb is determined (2)
    - detector (1)
    - current is proportional to the relative abundance (2)
  • State how and explain why the values of the first ionisation energies of Al and S deviate from the general trend (5)
    - both are lower and show a decrease (1)
    - in aluminium, the outer electron is in a 3p orbital (2)
    - 3p is higher in energy and more shielded (3)
    - in sulfur, electron is paired in a 3p orbital (4)
    - paired electrons repel so less energy is needed to remove it (5)
  • State and explain the general trend in the values of first ionisation energy of Na to Ar
    - general increase (1)
    - greater nuclear charge (2)
    - same shielding (3)
    - stronger attraction for outer electrons (4)
  • Explain why lithium has a higher first ionisation energy than potassium
    - the outermost electron in potassium is further from the nucleus
    And more shielding from the inner electrons
    - although nuclear charge is higher in potassium, this is far outweighed by greater distance and shielding
    - so potassium has a weaker electrostatic attraction on the outermost electron
    - so less energy is needed to remove the outermost electron
    - so lithium has a higher first ionisation energy
  • State 2 differences between the plum pudding model and the model of atomic structure used today
    - nucleus contains protons AND neutrons (1)
    - electrons are now arranged in energy levels/shells (2)
  • Explain the existence of a a peak which is smaller than the others (2)
    - 2+ ion is formed (1)
    - so it is 128/64=2 (2)
    Or 2 straight marks for 128 Te 2+
  • Define isotopes
    Atoms with the same number of protons but different number of neutrons
  • What is the mass spectrometer used for?
    To determine all the isotopes present in a sample of an element
    Therefore to identify elements
  • Why is electrospray ionisation used for larger organic molecules?
    Because the softer conditions of this technique means that fragmentation won‘t occur
  • Define successive ionisation energy
    The removal of more than one electron from the same atom
  • A decrease in first ionisation energy for aluminium is evidence for what?
    For atoms having sub shells
    The outermost electron is aluminium sits in a higher energy sub shell slightly further from the nucleus
    The atomic model Niels Bohr came up with didn’t explain sub shells