Periodicity

Cards (13)

  • define periodicity
    repeating trend/pattern
  • describe the atomic radius across period 3
    atomic radius decreases
    increased nuclear charge because there is an increased number of protons
    so there is a stronger electrostatic forces of attraction between outer electrons and nucleus
    and similar shielding
  • describe the trend in melting points in Na, Mg, Al
    they have metallic bonding
    general increase in melting points as there is an increasing positive charge, more delocalised electrons, so smaller atomic radius
    more energy required to break bonds
  • describe the trend in melting points in silicon
    has the highest melting point in period 3
    has a giant covalent structure
    there is lots of strong covalent bonds - lots of energy needed to overcome the strongbonds
  • describe the melting point in phosphorous and sunfurl
    phosphorous P4:
    has a simple molecular structure and has weak van der waals forces
    sulfur S8:
    higher melting point than P4 due to a larger simple molecular structure, so has more van der waals forces and so higher melting point
  • describe the melting point of chlorine and argon
    chlorine:
    lower melting point than P4 and S8 due to a smaller simple molecular structure and so smaller van der waals
    argon:
    has the lowest melting point because it exists individually, has the weakest van der waals forces
  • define ionisation energy
    The minimum amount of energy required to remove one mole of electrons from one mole of atoms in the gaseous state
    Endothermic reaction
  • what are the 3 factors affecting ionisation energy?
    shielding
    nuclear charge
    atomic radius
  • describe how shielding affects ionisation energy
    The more electron shells, the less energy required because the electrostatic forces of attraction are weaker
  • describe how nuclear charge affects ionisation energy
    the more protons in the nucleus, the stronger the electrostatic forces of attraction, so more energy required
    as long as shielding remains simillar
  • describe how atomic radius affects the ionisation energy
    the bigger the atom, the smaller the electrostatic forces of attractions, so less energy needed to remove an electron
  • describe the general trend in successive ionisation energy
    general increase in energy, because we are removing an electron from an increasingly positive ion
    There’s a jump between magnesium and aluminium in energy as removing electrons from a shell closer to the nucleus
  • describe the first ionisation energy trends down a group
    decreases down a group
    atomic radius increases going down the group, so the outer electrons are further from the nucleus
    so the electrostatic attraction is weaker
    energy required to remove an electron decreases
    shielding increases going down the group - more shells weaken the forces of attraction, so energy required to remove an electron decreases