Buffer solutions are solutions whose pH value changes only very slightly upon the addition of small amounts of either an acid or base
common-ion effect is the suppression of the ionization of a weak acid/base caused by adding more of an ion that is a product of this ionization to shift the equilibrium to the left (favour reactants).
A common example is adding strong acid/base to weak acid/base OR adding conjugateacid-base pair
Why can't strong acids and bases used to make buffer solutions?
because they will neutralise each other
Composition of common buffer solutions
weak acid and its conjugatebase
weak base and its conjugateacid
A buffer solution is an equilibrium between a weak acid and its conjugate base essentially, so Ka = [H+] for buffer solutions
a buffer is generally good for maintaining a nearly constant pH in a range of about 2 pH units centered on the pH of the buffer solution
Preparing buffer solutions
Weak acid + titrate with strongbase
Weak acid + saltofweakacid
Salt of weakacid + titrate with strongacid
Weak base + titrate with strongacid
Weak base + salt of weak base
Salt of weakbase + titrate with strongbase
How is buffer capacity maximised?
Highconcentration of buffer components
Equalconcentration of buffer components
HIn + H2O ⇌ H3O+ + In-
Add acid: IncreaseH3O+ = equilibrium shifts to left = [HIn] increase = show acid colour
HIn + H2O ⇌ H3O+ + In-
Basic solution added: DecreaseH3O+ = equilibrium shifts to right = [In-] increase = show base colour
[In-] / [HIn] <0.10 to show acid colour
[In-] / [HIn] =1 to show intermediate colour
[In-] / [HIn] >10 to show base colour
to show acid colour: pH < pK(HIn) -1
to show intermediate colour: pH = pK(HIn)
to show base colour: pH > pK(HIn) +1
Equivalence point in titration is the point which titrant added is enough to neutralise analyte solution
In strong acid - strong base titration, the pH at equivalence point is 7
In weak acid - strong base titration, the pH at equivalence point is higher than 7
In weak acid - strong base titration, pH = pKa and [HA] = [A-] at half neutralisation point
in the titration of weak polyprotic acid with a strong base, at the first equivalence point, the Ka2>Kb = H+ producing reaction dominates = pH is smaller than 7
in the titration of weak polyprotic acid with a strong base, at the second equivalence point, the Kb > Ka3 = OH- producing reaction dominates = pH is bigger than 7