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A-Level Chemistry
Module 2 - foundations
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Cards (113)
protons:
positively charged particles
in the
nucleus
of an
atom
that has a
mass
of
1
neutrons:
neutral subatomic
particle that has no
charge
and is found in the
nucleus
of an atom with a
mass
of
1
electrons:
negatively charged
particles in shells of an atom that have a relative mass of 0.0005
compound: a
substance
that contains
two
or more
elements chemically bonded
together
molecule: a group of
atoms
that are
chemically
bonded together with either
elements
or
compounds
mixture:
2
or more
elements
or
compounds
that are not
chemically
bonded together
ions
: atoms or molecules that has a
charge
due to the
loss
or
gain
of
electrons
isotope: an
atom
of an
element
with the same number of
protons
but a different number of
neutrons
Calculation:
number of neutrons =
mass
number -
atomic
number
relative atomic mass: the
average mass
of an atom compared to
1/12th
the
mass
of an atom of
carbon-12
Calculation:
Abundance
A)
percentage abundance
B)
total percentage
C)
mass number
3
mass spectroscopy: a way of
calculating
the
mass
of a sample
inject sample
vapourisation
ionised
to become
positive
ions
travel through a chamber /
magnetic
field
the
time
taken
to detector is measured
mass is calculated
Democritus (450BC):
He developed the
atomic
theory
if something is
invisible
it's still there
Dalton (1803):
Elements are
atoms
with different
masses
JJ Thompson (1897):
discovered the
negative electron
found by using
cathode
rays
atoms are
neutral
so something made it
positive
Rutherford (1909):
discovered the
positive
nucleus
alpha scatter
particle experiment
atoms are mostly
empty space
discovered the proton
Bohr (1913):
electrons
orbit the nucleus due to
electrostatic
forces and are in
shells
higher
frequencies of light have more
energy
eg./ gamma or Xray
Schrodinger (1927):
uses
probability
distribution for the different
energy
levels to show electrons are within a
cloud
instead of
shells
electrons are within
orbitals
Chadwick (1932):
discovered the
neutron
within the nucleus
Moles: the amount of a
substance
relative to the amount of
carbon
in
12
grams of carbon-12
Avogadro's constant: the number of atoms per
1
mol of
carbon-12
1
mol = 6.02 x1023
Calculation:
number of entities =
moles
x
6.02
x
1023
molar mass
: the mass of one mole of a substance in grams
Calculation:
Moles
m
o
l
e
s
=
moles =
m
o
l
es
=
m
a
s
s
/
M
r
mass/Mr
ma
ss
/
M
r
concentration: the amount of
solute
in a given
volume
of solution, measured in
mol
/dm3
volume: is a measure of the amount of
liquid
in
dm3
Calculation:
concentration
c
o
n
c
(
m
o
l
d
m
−
3
)
=
conc (moldm^-3) =
co
n
c
(
m
o
l
d
m
−
3
)
=
m
o
l
s
/
v
o
l
u
m
e
(
d
m
3
)
mols/volume (dm^3)
m
o
l
s
/
v
o
l
u
m
e
(
d
m
3
)
converting:
A)
/1000
B)
X1000
C)
metres 3
3
molar gas volume
: the volume per mole of gas molecules at a stated temp and pressure
RTP =
room temp
and
pressure
room temp =
20
degrees
room pressure =
101kPa
at RTP =
1
mol of gas has a volume of
24dm3
Calculation:
gas volume
m
o
l
e
s
=
moles =
m
o
l
es
=
v
o
l
u
m
e
(
d
m
3
)
/
g
a
s
v
o
l
u
m
e
(
d
m
3
)
volume (dm^3)/ gas volume (dm^3)
v
o
l
u
m
e
(
d
m
3
)
/
g
a
s
v
o
l
u
m
e
(
d
m
3
)
ideal gas assumptions:
random
motion
elastic
collision
negligible
size/
small
size
no
intermolecular
forces
Calculation:
ideal gas
p
r
e
s
s
u
r
e
(
P
a
)
×
v
o
l
u
m
e
(
m
3
)
=
pressure(Pa)×volume(m³) =
p
ress
u
re
(
P
a
)
×
v
o
l
u
m
e
(
m
3
)
=
m
o
l
s
×
g
a
s
c
o
n
s
t
a
n
t
(
m
o
l
−
1
K
−
1
)
×
t
e
m
p
(
K
)
mols×gas constant(mol^-1K^-1)×temp(K)
m
o
l
s
×
g
a
sco
n
s
t
an
t
(
m
o
l
−
1
K
−
1
)
×
t
e
m
p
(
K
)
lowest temperature:
absolute zero =
0K
(Kelvin)
0K = -273
0°C = 273K
theoretical yield: the
maximum
amount of
product
that can be made
100
% isn't possible due to
-
reactions
not completing
- other reactions
occurring
-
purifying
products
losses
products
actual yield < theoretical yield
Calculation:
percentage yield
p
e
r
c
e
n
t
a
g
e
y
i
e
l
d
=
percentage yield =
p
erce
n
t
a
g
ey
i
e
l
d
=
a
c
t
u
a
l
(
m
o
l
)
/
t
h
e
o
r
e
t
i
c
a
l
(
m
o
l
)
×
100
actual (mol)/theoretical (mol)× 100
a
c
t
u
a
l
(
m
o
l
)
/
t
h
eore
t
i
c
a
l
(
m
o
l
)
×
100
atom economy: the
ratio
of the amount of
product
formed to the amount of
reactants
used in a
chemical
reaction
efficient processes have
high
atom economies so they are
sustainable
Calculation:
Atom economy
a
t
o
m
e
c
o
n
o
m
y
=
atom economy =
a
t
o
m
eco
n
o
m
y
=
d
e
s
i
r
e
d
(
M
r
)
/
t
o
t
a
l
(
M
r
)
×
100
desired(Mr)/total(Mr) ×100
d
es
i
re
d
(
M
r
)
/
t
o
t
a
l
(
M
r
)
×
100
Empirical formula: The
simplest
whole number
ratio
of atoms of each
element
in a compound
find the
mass
of each
element
calculate the
moles
divide
by the
smallest
number
round
to a
whole
number
aqueous:
solid
dissolved in
water
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