X and Y are conditionally independent given Z (X⊥Y∣Z) if :
forall avlues x in Val(X) (same for ,y,z) : P(x∣y,z)=P(x∣z)
equivalent to : P(X,Y∣Z)=P(X∣Z)P(Y∣Z)
(L⊥D,I,S)
Is L completely independant of the other variables
L is conditionally independent of D,I,S given G, but not marginally independant
SO (L⊥D,I,S∣G)but(L⊥D,I,S)
SAT is conditionally independant of D,G,L given I
(G⊥L∣I,D)
G is not independant of L event if we know I and D, Knowledge of L helps us to better guess G even if we know I and D
G is conditionally independant of S, given I and D
D and I are independant
Given the values of its parents, a variable X is independent from all other
variables in the network that are not its children and, more generally, its
descendants.
information about X’s descendants can change our belief about X
(via an evidential reasoning process)
X’s parents “shield” X from causal influences further up in the network
In a Bayesian Network, every variable is conditionally independant of all its non-descendants, given tis parents
A Bayesian Network Structure G is a directly acyclic graph whose nodes represent a set of random variables X = {X1, ..., Xn} Given a structure G, the following conditional independencies hold :
(Xi⊥NonDesc(Xi)∣Pa(Xi)),∀Xi∈X
In a Bayesian Network, every variable is condtionally independant of all its non-descendants, given its parents
If the network graph correctly represents the conditional independencies in
the joint distribution P over X , then this full joint distribution P can be