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Z - Old
Probalistc Models
Math - part 2,3
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Cards (8)
(
G
⊥̸
L
∣
I
,
D
)
(G \not \bot L | I,D)
(
G
⊥
L
∣
I
,
D
)
G is
not independant
of L
G is
conditionally independ
of S, given I and D
D is
independant
of I and S
(
D
⊥
I
,
S
)
(D \bot I, S)
(
D
⊥
I
,
S
)
P
(
D
,
I
,
G
,
S
,
L
)
=
P(D,I,G,S,L) =
P
(
D
,
I
,
G
,
S
,
L
)
=
P
(
D
)
P
(
I
)
P
(
G
∣
D
,
I
)
P
(
S
∣
I
)
P
(
L
∣
G
)
P(D) P(I) P(G|D,I) P(S|I) P(L|G)
P
(
D
)
P
(
I
)
P
(
G
∣
D
,
I
)
P
(
S
∣
I
)
P
(
L
∣
G
)
P
(
D
∣
g
3
,
s
1
)
=
P(D|g^3, s^1) =
P
(
D
∣
g
3
,
s
1
)
=
1
Z
[
P
(
d
0
,
g
3
,
s
1
)
P
(
d
1
,
g
3
,
s
1
)
]
\frac{1}{Z} [ P(d^0, g^3, s^1) P(d^1, g^3, s^1)]
Z
1
[
P
(
d
0
,
g
3
,
s
1
)
P
(
d
1
,
g
3
,
s
1
)]
A)
i0,i1
B)
l0l1
2
Estimating the probability
A)
27
B)
1000
2
Rejection sampling
A)
G,S,L
B)
i1
C)
31
D)
84
4
Sample-Likelihood weighting
A)
1.0
B)
d0,d1
C)
i0,i1
D)
evidence
E)
0.7
F)
s1|i0
6