9.4 Defining and Differentiating Vector-Valued Functions

Cards (27)

  • The vector-valued function r(t)\vec{r}(t) represents the position of a moving object as a function of the parameter t.
  • The vector-valued function r(t)\vec{r}(t) represents the velocity of a moving object.

    False
  • What is a vector-valued function?
    A function that assigns a vector to each input value
  • What is a vector-valued function?
    Assigns a vector to each input
  • A vector-valued function can be written as \vec{r}(t).
  • Match the component of a vector-valued function with its description:
    x(t)x(t) ↔️ The x-coordinate function
    y(t)y(t) ↔️ The y-coordinate function
    z(t)z(t) ↔️ The z-coordinate function
  • What does the vector-valued function r(t)\vec{r}(t) represent?

    Position of a moving object
  • A vector-valued function can be written as r(t)=\vec{r}(t) =x(t),y(t),z(t) \langle x(t), y(t), z(t)\rangle, where x(t)x(t), y(t)y(t), and z(t)z(t) are the components
  • The component x(t)x(t) in a vector-valued function represents the x-coordinate of the function.

    True
  • What does the vector-valued function r(t)\vec{r}(t) represent?

    The position of a moving object
  • To graph a vector-valued function, you plot points defined by the parametric equations x(t)x(t), y(t)y(t), and z(t)z(t).
  • Each value of tt in a vector-valued function corresponds to a unique position vector.

    True
  • How is the derivative of a vector-valued function calculated?
    By differentiating each component function
  • The derivative of r(t)=\vec{r}(t) =x(t),y(t),z(t) \langle x(t), y(t), z(t)\rangle is r(t)=\vec{r}'(t) =x(t),y(t),z(t) \langle x'(t), y'(t), z'(t)\rangle, where x(t)x'(t), y(t)y'(t), and z(t)z'(t) are the derivatives of x(t)x(t), y(t)y(t), and z(t)z(t).
  • Steps to graph the vector-valued function r(t)=\vec{r}(t) =t2,t \langle t^{2}, t \rangle
    1️⃣ Create a table of values for tt, x(t)x(t), and y(t)y(t)
    2️⃣ Plot the points on a coordinate plane
    3️⃣ Connect the points to create the curve
  • Each value of tt corresponds to a position vector
  • Steps to create the curve for a vector-valued function
    1️⃣ Choose values for tt
    2️⃣ Calculate x(t)x(t) and y(t)y(t)
    3️⃣ Plot the points
    4️⃣ Connect the points to create the curve
  • The Sum Rule for differentiating vector-valued functions states that ddt[u(t)+\frac{d}{dt}[\vec{u}(t) +v(t)]= \vec{v}(t)] =u(t)+ \vec{u}'(t) +v(t) \vec{v}'(t)
    True
  • The Product Rule for Dot Products states that ddt[u(t)v(t)]=\frac{d}{dt}[\vec{u}(t) \cdot \vec{v}(t)] =u(t)v(t)+ \vec{u}'(t) \cdot \vec{v}(t) +u(t)v(t) \vec{u}(t) \cdot \vec{v}'(t) is the derivative
  • What is the formula for the Product Rule for Cross Products?
    ddt[u(t)×v(t)]=\frac{d}{dt}[\vec{u}(t) \times \vec{v}(t)] =u(t)×v(t)+ \vec{u}'(t) \times \vec{v}(t) +u(t)×v(t) \vec{u}(t) \times \vec{v}'(t)
  • The velocity of an object is the derivative of its position vector with respect to time
    True
  • What is the formula for arc length along a curve defined by a vector-valued function?
    s=s =abv(t)dt \int_{a}^{b} ||\vec{v}(t)|| dt
  • If r(t)=\vec{r}(t) =t2,sin(t),et \langle t^{2}, \sin(t), e^{t} \rangle, then r(t)=\vec{r}'(t) =2t,cos(t),et \langle 2t, \cos(t), e^{t} \rangle is correct.

    True
  • Match the component with its function in \vec{r}(t) = \langle t^{2}, \sin(t), e^{t} \rangle</latex>:
    x(t)x(t) ↔️ t2t^{2}
    y(t)y(t) ↔️ sin(t)\sin(t)
    z(t)z(t) ↔️ ete^{t}
  • Graphing vector-valued functions involves plotting points defined by parametric equations
    True
  • What is the formula for the derivative of a vector-valued function r(t)\vec{r}(t)?

    r(t)=\vec{r}'(t) =x(t),y(t),z(t) \langle x'(t), y'(t), z'(t)\rangle
  • If \vec{r}(t) = \langle t^{2}, \sin(t), e^{t} \rangle</latex>, then r(t)=\vec{r}'(t) =2t,cos(t),et \langle 2t, \cos(t), e^{t} \rangle is the derivative