8.9 Volume with Disc Method: Revolving Around the x- or y-Axis

Cards (117)

  • The disc method calculates the volume of a solid of revolution by slicing it into thin discs
  • Match the axis of revolution with the correct volume formula:
    x-axis ↔️ ∫ π [f(x)]² dx
    y-axis ↔️ ∫ π [g(y)]² dy
  • What is the disc radius when revolving around the y-axis?
    g(y)
  • The disc method requires slicing the solid into discs perpendicular to the axis of revolution.

    True
  • What is the volume of the solid formed by revolving f(x) = √x around the x-axis from x = 0 to x = 4?
  • The formula for revolving around the x-axis is V = ∫ π [f(x)]² dx.
    True
  • When revolving around the y-axis, the disc radius is given by g(y).
    True
  • What is the volume of the solid formed by revolving g(y) = √y around the y-axis from y = 0 to y = 9?
    81π/2
  • What is the volume formula for revolving around the y-axis?
    ∫ π [g(y)]² dy
  • The general formula for calculating volume using the disc method when revolving around the y-axis is ∫ π [g(y)]² dy
  • Match the axis of revolution with the correct volume formula:
    x-axis ↔️ ∫ π [f(x)]² dx
    y-axis ↔️ ∫ π [g(y)]² dy
  • The disc method uses integration to sum the volumes of thin discs to find the total volume of a solid.

    True
  • What is the disc radius when revolving around the x-axis?
    f(x)
  • The volume of each disc is calculated as πr²h, where r is the radius
  • Steps to calculate the volume of a solid formed by revolving f(x) = √x around the x-axis from x = 0 to x = 4
    1️⃣ Square the function: [f(x)]² = x
    2️⃣ Multiply by π: π [f(x)]² = πx
    3️⃣ Integrate over the interval: ∫ πx dx
    4️⃣ Evaluate the definite integral: 8π
  • The volume of each disc is calculated as πr²h, where h is the thickness
  • Steps to calculate the volume of a solid formed by revolving f(x) = √x around the x-axis from x = 0 to x = 4
    1️⃣ Square the function: [f(x)]² = x
    2️⃣ Multiply by π: π [f(x)]² = πx
    3️⃣ Integrate over the interval: ∫ πx dx
    4️⃣ Evaluate the definite integral: 8π
  • Revolving f(x) = √x around the x-axis from x = 0 to x = 4 yields a volume of
  • What is the formula for revolving around the y-axis using the disc method?
    V = ∫ π [g(y)]² dy
  • Steps to calculate the volume of a solid formed by revolving g(y) = √y around the y-axis from y = 0 to y = 9
    1️⃣ Square the function: [g(y)]² = y
    2️⃣ Multiply by π: π [g(y)]² = πy
    3️⃣ Integrate over the interval: ∫ πy dy
    4️⃣ Evaluate the definite integral: 81π/2
  • When revolving around the x-axis, the volume formula is ∫ π [f(x)]² dx
  • What is represented by 'V' in the volume formula for the disc method?
    Volume
  • When revolving around the x-axis, the volume formula uses the function f(x).

    True
  • The volume of each disc in the disc method is calculated using the formula πr²h
  • What is the volume of the solid formed by revolving f(x) = √x around the x-axis from x = 0 to x = 4?
  • What is the final volume of the solid formed by revolving f(x) = √x around the x-axis from x = 0 to x = 4?
  • Revolving g(y) = √y around the y-axis from y = 0 to y = 9 results in a volume of 81π/2 cubic units.

    True
  • The integral setup for the x-axis rotation involves squaring the function and multiplying by π
  • The volume formula for x-axis rotation is V = ∫ π [f(x)]² dx
  • What is the squared value of f(x) = x²?
    x4x^{4}
  • To calculate the volume of a solid formed by revolving a region around the x-axis, we multiply by π
  • In the volume formula for x-axis rotation, the function is first squared
  • What is the key difference between x-axis and y-axis rotation in volume calculation?
    Function and variable
  • The volume formula for y-axis rotation uses g(y) as the function.

    True
  • What is the squared value of f(x) = √x?
    x
  • The volume of the solid is cubic units.
  • For f(x) = √x, the square of the function is x.
  • When revolving f(x) = √x around the x-axis, the expression π [f(x)]² simplifies to πx.
  • Steps to calculate the volume of a solid formed by revolving f(x) = √x around the x-axis from x = 0 to x = 4
    1️⃣ [f(x)]² = x
    2️⃣ π [f(x)]² = πx
    3️⃣ ∫ from 0 to 4 (πx) dx = 8π
  • For g(y) = √y, the square of the function is y.