6.15 Finding Specific Antiderivatives Using Initial Conditions: Motion Applications

Cards (88)

  • What are initial conditions used for in motion problems?
    Determining specific antiderivatives
  • What does v(t0)=v(t_{0}) =v0 v_{0} represent in motion problems?

    Initial velocity
  • What is the constant of integration in a general antiderivative?
    An arbitrary constant
  • What is the purpose of initial conditions in motion problems?
    Solving for specific antiderivatives
  • <question_start>The initial condition for position is represented as s(t0)=s(t_{0}) =s0 s_{0}, where s0s_{0} is the initial position
  • What is the arbitrary constant added to a general antiderivative called?
    Constant of integration
  • <question_start>The general antiderivative of cos(x)\cos(x) is sin(x)+\sin(x) + C
  • \int f(x) dx = F(x) + C
  • What does the general antiderivative represent?
    All possible functions
  • The general antiderivative provides the set of all possible functions that could have been differentiated to obtain the original function.

    True
  • What does s(t_{0}) = s_{0}</latex> represent in motion problems?
    Initial position
  • Substituting the initial condition into the general antiderivative allows us to determine the unique function.
    True
  • In motion problems, t0t_{0} represents the initial time
  • Match the variable with its description in motion problems:
    s0s_{0} ↔️ Initial position
    v0v_{0} ↔️ Initial velocity
  • The general antiderivative of x2x^{2} is \frac{x^{3}}{3} + C
  • What is the constant CC called in indefinite integration?

    Constant of integration
  • Steps to find the specific antiderivative using initial conditions
    1️⃣ Start with the general antiderivative
    2️⃣ Solve for the constant of integration CC
  • What role do initial conditions play in motion applications of integration?
    Solve for the constant CC
  • s(0)=s(0) =02+ 0^{2} +C    C= C \implies C =10 10, which means s(0)=s(0) =10 10 is the initial position
  • The general antiderivative of v(t)v(t) is expressed as v(t)dt=\int v(t) dt =F(t)+ F(t) +C C, where C represents the constant of integration
  • What is the value of C if the velocity function is v(t)=v(t) =2t 2t and s(0)=s(0) =10 10?

    10
  • Match the variable with its mathematical representation:
    Position ↔️ v(t)dt=\int v(t) dt =F(t)+ F(t) +C C
    Initial condition ↔️ s(t0)=s(t_{0}) =s0 s_{0}
    Velocity ↔️ v(t)v(t)
  • What is the value of C if the general antiderivative for position is s(t)=s(t) =12t2+ \frac{1}{2}t^{2} +C C and the initial condition is s(0)=s(0) =5 5?

    5
  • The specific antiderivative for s(t)=s(t) =12t2+ \frac{1}{2}t^{2} +C C with s(0) = 5</latex> is s(t)=s(t) =12t2+ \frac{1}{2}t^{2} +5 5, where C is equal to 5
  • In the initial condition s(t_{0}) = s_{0}</latex>, t0t_{0} represents the initial time
  • What does an initial condition provide in motion problems?
    Known value of position
  • <statement_start>Initial conditions such as v(t0)=v(t_{0}) =v0 v_{0} help find the specific antiderivative
  • Match the term with its description:
    General antiderivative ↔️ Function whose derivative is f(x)f(x)
    Constant of integration ↔️ Arbitrary constant added to antiderivative
    Indefinite integral ↔️ Process to find antiderivatives
  • What is the general antiderivative of cos(x)\cos(x)?

    sin(x)+\sin(x) +C C
  • Steps to find the specific antiderivative using initial conditions:
    1️⃣ Find the general antiderivative of v(t)v(t) or a(t)a(t)
    2️⃣ Substitute the initial condition into the general antiderivative
    3️⃣ Solve for the constant of integration CC
    4️⃣ Replace CC in the general antiderivative to get the specific antiderivative
  • <statement_start>Initial conditions provide known values of position, velocity, or acceleration at a particular time
  • What is the specific position function for v(t)=v(t) =2t 2t and s(0) = 3</latex>?

    s(t)=s(t) =t2+ t^{2} +3 3
  • <statement_start>To find the specific position function, we use the initial position to solve for the constant of integration
  • What is the position function for v(t)=v(t) =2t 2t and s(0)=s(0) =5 5?

    s(t)=s(t) =t2+ t^{2} +5 5
  • What is the general antiderivative of v(t)=v(t) =2t 2t?

    s(t)=s(t) =t2+ t^{2} +C C
  • What is the value of CC in the specific antiderivative s(t) = t^{2} + C</latex> given s(0)=s(0) =5 5?

    C=C =5 5
  • An initial condition allows you to find the constant of integration
  • What initial condition is used to find velocity given acceleration in motion problems?
    v(t0)=v(t_{0}) =v0 v_{0}
  • What is the general antiderivative of v(t)=v(t) =2t 2t?

    s(t)=s(t) =t2+ t^{2} +C C
  • What is the specific antiderivative of v(t)=v(t) =2t 2t with s(0) = 3</latex>?

    s(t)=s(t) =t2+ t^{2} +3 3