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AP Calculus BC
Unit 6: Integration and Accumulation of Change
6.15 Finding Specific Antiderivatives Using Initial Conditions: Motion Applications
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What are initial conditions used for in motion problems?
Determining specific antiderivatives
What does
v
(
t
0
)
=
v(t_{0}) =
v
(
t
0
)
=
v
0
v_{0}
v
0
represent in motion problems?
Initial velocity
What is the constant of integration in a general antiderivative?
An arbitrary constant
What is the purpose of initial conditions in motion problems?
Solving for specific antiderivatives
<question_start>The initial condition for position is represented as
s
(
t
0
)
=
s(t_{0}) =
s
(
t
0
)
=
s
0
s_{0}
s
0
, where
s
0
s_{0}
s
0
is the initial position
What is the arbitrary constant added to a general antiderivative called?
Constant of integration
<question_start>The general antiderivative of
cos
(
x
)
\cos(x)
cos
(
x
)
is
sin
(
x
)
+
\sin(x) +
sin
(
x
)
+
C
\int f(x) dx = F(x) +
C
What does the general antiderivative represent?
All possible functions
The general antiderivative provides the set of all possible functions that could have been
differentiated
to obtain the original function.
True
What does s(t_{0}) = s_{0}</latex> represent in motion problems?
Initial position
Substituting the initial condition into the general antiderivative allows us to determine the unique function.
True
In motion problems,
t
0
t_{0}
t
0
represents the initial time
Match the variable with its description in motion problems:
s
0
s_{0}
s
0
↔️ Initial position
v
0
v_{0}
v
0
↔️ Initial velocity
The general antiderivative of
x
2
x^{2}
x
2
is \frac{x^{3}}{3} + C
What is the constant
C
C
C
called in indefinite integration?
Constant of integration
Steps to find the specific antiderivative using initial conditions
1️⃣ Start with the general antiderivative
2️⃣ Solve for the constant of integration
C
C
C
What role do initial conditions play in motion applications of integration?
Solve for the constant
C
C
C
s
(
0
)
=
s(0) =
s
(
0
)
=
0
2
+
0^{2} +
0
2
+
C
⟹
C
=
C \implies C =
C
⟹
C
=
10
10
10
, which means
s
(
0
)
=
s(0) =
s
(
0
)
=
10
10
10
is the initial position
The general antiderivative of
v
(
t
)
v(t)
v
(
t
)
is expressed as
∫
v
(
t
)
d
t
=
\int v(t) dt =
∫
v
(
t
)
d
t
=
F
(
t
)
+
F(t) +
F
(
t
)
+
C
C
C
, where C represents the constant of integration
What is the value of C if the velocity function is
v
(
t
)
=
v(t) =
v
(
t
)
=
2
t
2t
2
t
and
s
(
0
)
=
s(0) =
s
(
0
)
=
10
10
10
?
10
Match the variable with its mathematical representation:
Position ↔️
∫
v
(
t
)
d
t
=
\int v(t) dt =
∫
v
(
t
)
d
t
=
F
(
t
)
+
F(t) +
F
(
t
)
+
C
C
C
Initial condition ↔️
s
(
t
0
)
=
s(t_{0}) =
s
(
t
0
)
=
s
0
s_{0}
s
0
Velocity ↔️
v
(
t
)
v(t)
v
(
t
)
What is the value of C if the general antiderivative for position is
s
(
t
)
=
s(t) =
s
(
t
)
=
1
2
t
2
+
\frac{1}{2}t^{2} +
2
1
t
2
+
C
C
C
and the initial condition is
s
(
0
)
=
s(0) =
s
(
0
)
=
5
5
5
?
5
The specific antiderivative for
s
(
t
)
=
s(t) =
s
(
t
)
=
1
2
t
2
+
\frac{1}{2}t^{2} +
2
1
t
2
+
C
C
C
with s(0) = 5</latex> is
s
(
t
)
=
s(t) =
s
(
t
)
=
1
2
t
2
+
\frac{1}{2}t^{2} +
2
1
t
2
+
5
5
5
, where C is equal to 5
In the initial condition s(t_{0}) = s_{0}</latex>,
t
0
t_{0}
t
0
represents the initial time
What does an initial condition provide in motion problems?
Known value of position
<statement_start>Initial conditions such as
v
(
t
0
)
=
v(t_{0}) =
v
(
t
0
)
=
v
0
v_{0}
v
0
help find the specific antiderivative
Match the term with its description:
General antiderivative ↔️ Function whose derivative is
f
(
x
)
f(x)
f
(
x
)
Constant of integration ↔️ Arbitrary constant added to antiderivative
Indefinite integral ↔️ Process to find antiderivatives
What is the general antiderivative of
cos
(
x
)
\cos(x)
cos
(
x
)
?
sin
(
x
)
+
\sin(x) +
sin
(
x
)
+
C
C
C
Steps to find the specific antiderivative using initial conditions:
1️⃣ Find the general antiderivative of
v
(
t
)
v(t)
v
(
t
)
or
a
(
t
)
a(t)
a
(
t
)
2️⃣ Substitute the initial condition into the general antiderivative
3️⃣ Solve for the constant of integration
C
C
C
4️⃣ Replace
C
C
C
in the general antiderivative to get the specific antiderivative
<statement_start>Initial conditions provide known values of position, velocity, or acceleration at a particular
time
What is the specific position function for
v
(
t
)
=
v(t) =
v
(
t
)
=
2
t
2t
2
t
and s(0) = 3</latex>?
s
(
t
)
=
s(t) =
s
(
t
)
=
t
2
+
t^{2} +
t
2
+
3
3
3
<statement_start>To find the specific position function, we use the initial position to solve for the constant of
integration
What is the position function for
v
(
t
)
=
v(t) =
v
(
t
)
=
2
t
2t
2
t
and
s
(
0
)
=
s(0) =
s
(
0
)
=
5
5
5
?
s
(
t
)
=
s(t) =
s
(
t
)
=
t
2
+
t^{2} +
t
2
+
5
5
5
What is the general antiderivative of
v
(
t
)
=
v(t) =
v
(
t
)
=
2
t
2t
2
t
?
s
(
t
)
=
s(t) =
s
(
t
)
=
t
2
+
t^{2} +
t
2
+
C
C
C
What is the value of
C
C
C
in the specific antiderivative s(t) = t^{2} + C</latex> given
s
(
0
)
=
s(0) =
s
(
0
)
=
5
5
5
?
C
=
C =
C
=
5
5
5
An initial condition allows you to find the constant of
integration
What initial condition is used to find velocity given acceleration in motion problems?
v
(
t
0
)
=
v(t_{0}) =
v
(
t
0
)
=
v
0
v_{0}
v
0
What is the general antiderivative of
v
(
t
)
=
v(t) =
v
(
t
)
=
2
t
2t
2
t
?
s
(
t
)
=
s(t) =
s
(
t
)
=
t
2
+
t^{2} +
t
2
+
C
C
C
What is the specific antiderivative of
v
(
t
)
=
v(t) =
v
(
t
)
=
2
t
2t
2
t
with s(0) = 3</latex>?
s
(
t
)
=
s(t) =
s
(
t
)
=
t
2
+
t^{2} +
t
2
+
3
3
3
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