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AP Calculus BC
Unit 5: Analytical Applications of Differentiation
5.8 Connecting Position, Velocity, and Acceleration
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Cards (33)
In the context of motion, position is denoted by
s(t)
Match the term with its derivative:
Position ↔️ Velocity
Velocity ↔️ Acceleration
Acceleration ↔️ a'(t)
Velocity indicates how quickly and in what direction an object's
position
is changing.
True
The velocity of an object at time
t
is denoted by `v(t)`.
Acceleration tells us how quickly the
velocity
is changing.
True
The derivative of velocity is acceleration, denoted as `v'(t) =
a(t)
`.
True
If `s(t) = 2t^3 - 4t^2 + 3t + 1`, then the velocity is
6t^2 - 8t + 3
.
What is the derivative relationship between position and velocity?
v(t) = s'(t)
If `s(t) = 2t^3 - 4t^2 + 3t + 1`, then the velocity is `v(t) = 6t^2 - 8t +
3
How is velocity calculated from position using derivatives?
v(t) = s'(t)
Acceleration is the
rate of change
of velocity.
True
Position, velocity, and
acceleration
are all defined in terms of time.
True
What does velocity tell us about an object's position?
How quickly it changes
How is acceleration mathematically related to velocity?
a(t) = v'(t)
What is the first step to find velocity from a position function?
Take the first derivative
If `s(t) = 3t^2 - 5t + 2`, then the acceleration is `a(t) =
6
What is the velocity for the position function `s(t) = 2t^3 - 4t^2 + 3t + 1`?
6t^2 - 8t + 3
Velocity is the first
derivative
of position.
True
Acceleration is the rate of change of
velocity
Match the term with its definition:
Position ↔️ Location of object at time t
Velocity ↔️ Rate of change of position
The relationship between position and velocity is given by `v(t) =
s'(t)
`.
True
Acceleration is the derivative of
velocity
with respect to time.
The derivative of velocity, `v'(t)`, gives the
acceleration
of the object.
Match the term with its derivative:
Position ↔️ Velocity
Velocity ↔️ Acceleration
Velocity is the rate of change of
position
.
True
If `s(t) = 2t^3 - 4t^2 + 3t + 1`, then the acceleration is `a(t) = 12t -
8
How is acceleration calculated from velocity using derivatives?
a(t) = v'(t)
What is the derivative of position with respect to time?
Velocity
If `s(t) = 2t^2 - 3t + 1`, then the velocity is `v(t) = 4t -
3
If `v(t) = 3t^2 - 6t + 2`, then the acceleration is `a(t) = 6t -
6
If `s(t) = 3t^2 - 5t + 2`, then the
velocity
is `v(t) = 6t - 5`.
True
Acceleration is the rate of change of velocity.
True
If `s(t) = 2t^3 - 4t^2 + 3t + 1`, then the acceleration is `a(t) = 12t -
8