5.2 Extreme Value Theorem, Global Versus Local Extrema

Cards (102)

  • The Extreme Value Theorem applies only to continuous functions on closed intervals.

    True
  • Techniques for finding absolute extrema on closed intervals include checking critical points and endpoints
  • What is one application of the Extreme Value Theorem in problem solving?
    Finding absolute extrema
  • Global extrema are the absolute maximum and minimum values of a function over its entire domain.

    True
  • Local extrema are the relative maximum and minimum values in a local region.
  • The Extreme Value Theorem requires a function to be continuous on a closed interval to guarantee global extrema.

    True
  • The Extreme Value Theorem requires that the function f(x) must be defined on a closed interval.
  • Where can local extrema occur in relation to the derivative of a function?
    At critical points
  • Match the type of extrema with its definition:
    Global Extrema ↔️ Absolute maximum/minimum over entire domain
    Local Extrema ↔️ Relative maximum/minimum in a local region
  • What are the two primary methods for identifying critical points?
    f'(x) = 0 or undefined
  • What are the critical points of f(x) = x^3 - 6x^2 + 5?
    x = 0, x = 4
  • What is the definition of global extrema?
    Absolute max/min over domain
  • What does the Extreme Value Theorem state?
    Global max and min exist
  • What is the difference between global and local extrema?
    Absolute versus relative values
  • Steps for finding local extrema using the first derivative test
    1️⃣ Find the derivative f'(x)
    2️⃣ Set f'(x) = 0 and solve for x
    3️⃣ Determine critical points
    4️⃣ Analyze the sign of f'(x) around critical points
  • What interval condition is required for the Extreme Value Theorem?
    Closed interval
  • Where may global extrema occur within the closed interval [a, b]?
    Critical points or endpoints
  • Where may local extrema occur within the domain of a function?
    Anywhere in the domain
  • What does the continuity condition ensure for the Extreme Value Theorem?
    No breaks in the graph
  • Global extrema represent the absolute maximum and minimum values of a function over its entire domain.

    True
  • What two conditions must be met for the Extreme Value Theorem to apply?
    Continuity and closed interval
  • Critical points are values of x where the derivative f'(x) is either zero or undefined.
  • Critical points occur where the derivative of a function is undefined because the function's slope may be vertical or have a cusp.

    True
  • What two conditions must be met for the Extreme Value Theorem to apply?
    Continuity and closed interval
  • Global extrema are located within the closed interval
  • What does the Extreme Value Theorem state?
    Continuous functions have extrema
  • The Extreme Value Theorem requires the function to be continuous on the entire closed interval
  • Match the characteristic with the type of extrema:
    Definition ↔️ Absolute max/min over domain
    Location ↔️ Within closed interval
  • Local extrema may occur anywhere in the domain.
    True
  • What condition does the Extreme Value Theorem require for a function on a closed interval?
    Continuity
  • What are the two methods for identifying critical points?
    Derivative equals zero or undefined
  • Critical points are important for identifying both global and local extrema.

    True
  • Critical points are important for identifying both global and local extrema
  • Match the type of extrema with its definition:
    Global Extrema ↔️ Absolute max/min over entire domain
    Local Extrema ↔️ Relative max/min in a local region
  • To find critical points, one method is to set the derivative equal to zero
  • Steps for finding critical points using the derivative method:
    1️⃣ Find the derivative f'(x)
    2️⃣ Set f'(x) = 0
    3️⃣ Solve for x
  • The Extreme Value Theorem applies to functions that are continuous on a closed interval.
  • What is the derivative of f(x) = x^3 - 6x^2 + 5?
    3x^2 - 12x
  • What are the critical points of f(x) = x^3 - 6x^2 + 5?
    0 and 4
  • A local maximum occurs when f'(x) changes from positive to negative.

    True