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AP Calculus BC
Unit 2: Differentiation: Definition and Fundamental Properties
2.11 The Chain Rule
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The Chain Rule is used to differentiate
composite
functions.
True
Differentiate `y = sin(x^2)` using the Chain Rule.
`dy/dx = 2x cos(x^2)`
The outer function in a composite function is the function that the entire expression is inside
of
The Chain Rule formula `dy/dx = dy/du * du/dx` requires differentiating both the outer and
inner
functions.
True
Consider `y = (x^2 + 3)^4`. Identify the outer and inner functions.
Outer: `u^4`, Inner: `x^2 + 3`
The Chain Rule is used specifically for differentiating
composite
functions.
What is the derivative of `y = sin(x^2)` using the Chain Rule?
`dy/dx = 2x cos(x^2)`
In `y = sin(3x^2 + 1)`, the outer function is `f(u) = sin(u)`.
True
What rule is used to differentiate a composite function?
Chain Rule
The inner function in a
composite function
is often a more complex expression.
True
The inner function in y = sin(3x^2 + 1) is
3x^2 + 1
After identifying the outer function, the next step is to differentiate it with respect to
u
Find the derivative of y = (x^2 + 1)^3 using the Chain Rule.
6x(x^2 + 1)^2
Match the concept with its description:
Differentiating Outer Function ↔️ Finding the derivative of f(u)
Chain Rule ↔️ Differentiating the entire composite function
In the Chain Rule, dy/du represents the derivative of the outer function with respect to the
inner
What is the formula for the Chain Rule when `y = f(u)` and `u = g(x)`?
`dy/dx = dy/du * du/dx`
The Product Rule has the formula
(uv)' = u'v + uv'
The Chain Rule applies to
functions
where one function is nested inside another.
True
What is the role of the inner function in a composite function?
Input to the outer function
In the Chain Rule, `du/dx` is the derivative of the inner function with respect to
x
Steps to differentiate `y = (x^2 + 3)^4` using the Chain Rule.
1️⃣ Differentiate the outer function: `dy/du = 4u^3`
2️⃣ Substitute `u = x^2 + 3`: `dy/du = 4(x^2 + 3)^3`
3️⃣ Multiply by the derivative of the inner function: `dy/dx = 8x(x^2 + 3)^3`
The Chain Rule formula remains the same regardless of the complexity of the inner function.
True
The outer function in a composite function encloses the entire composite
expression
Match the function type with its definition:
Outer Function ↔️ Primary function enclosing the composite expression
Inner Function ↔️ The function inside the outer function
The outer function in a composite expression is denoted as
f(u)
Identify the outer function in y = sin(3x^2 + 1).
sin(u)
What is the first step in differentiating the outer function in the Chain Rule?
Identify f(u)
The derivative of the entire composite function dy/dx is obtained by multiplying f'(g(x)) by
g'(x)
.
True
Differentiating the outer function involves finding f'(g(x)), which means differentiating f(u) with respect to
g(x)
What is the formula for the Chain Rule?
d
y
/
d
x
=
dy / dx =
d
y
/
d
x
=
d
y
/
d
u
∗
dy / du *
d
y
/
d
u
∗
d
u
/
d
x
du / dx
d
u
/
d
x
The Chain Rule requires multiplying the
derivatives
of the outer and inner functions.
True
The final derivative of a composite function in the Chain Rule is found using the formula
dy/dx = dy/du * du/dx
Match the differentiation rule with its formula:
Chain Rule ↔️
d
y
/
d
x
=
dy / dx =
d
y
/
d
x
=
d
y
/
d
u
∗
dy / du *
d
y
/
d
u
∗
d
u
/
d
x
du / dx
d
u
/
d
x
Product Rule ↔️
(
u
v
)
′
=
(uv)' =
(
uv
)
′
=
u
′
v
+
u'v +
u
′
v
+
u
v
′
uv'
u
v
′
Quotient Rule ↔️
(
u
/
v
)
′
=
(u / v)' =
(
u
/
v
)
′
=
(
u
′
v
−
u
v
′
)
/
v
2
(u'v - uv') / v^{2}
(
u
′
v
−
u
v
′
)
/
v
2
The Chain Rule formula is `dy/dx = dy/du *
du/dx
What does `du/dx` represent in the Chain Rule formula?
Inner function derivative
The Product Rule and
Quotient Rule
are used to differentiate products and quotients of functions, respectively.
True
What is the Chain Rule used to differentiate?
Composite functions
Steps to identify the outer and inner functions for the Chain Rule:
1️⃣ Identify the outer function \( f(u) \)
2️⃣ Identify the inner function \( g(x) \)
The inner function acts as the input \( u \) for the
outer
What is the formula for differentiating the outer function using the Chain Rule?
d
y
d
x
=
\frac{dy}{dx} =
d
x
d
y
=
d
y
d
u
⋅
d
u
d
x
\frac{dy}{du} \cdot \frac{du}{dx}
d
u
d
y
⋅
d
x
d
u
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