Cards (51)

  • What is the form of an explicit function?
    y=y =f(x) f(x)
  • In the chain rule for implicit functions, ddx[f(y)]\frac{d}{dx} [f(y)] is equal to f(y)dydxf'(y) \cdot \frac{dy}{dx}, where dydx\frac{dy}{dx} represents the derivative
  • Implicit differentiation is used when both variables are dependent on each other.
  • Steps to perform implicit differentiation
    1️⃣ Differentiate both sides of the equation
    2️⃣ Use the chain rule for terms involving both variables
    3️⃣ Solve for the derivative of the dependent variable
  • In an explicit function, one variable is expressed directly in terms of the other.
  • What is the general form of an implicit function?
    F(x,y)=F(x, y) =0 0
  • In the example x2+x^{2} +y2= y^{2} =25 25, the derivative dydx\frac{dy}{dx} is equal to xy- \frac{x}{y}
  • Steps in implicit differentiation
    1️⃣ Differentiate each term with respect to xx
    2️⃣ Apply the chain rule where necessary
    3️⃣ Solve for dydx\frac{dy}{dx}
  • What is the purpose of checking the implicit differentiation solution with an explicit form?
    To verify the derivative
  • What is dydx\frac{dy}{dx} when differentiating x2+x^{2} +y2= y^{2} =25 25?

    dydx=\frac{dy}{dx} =xy - \frac{x}{y}
  • Explicit differentiation is used when relationships are not easily expressed explicitly.
    False
  • Steps for solving dydx\frac{dy}{dx} in implicit differentiation

    1️⃣ Isolate terms containing dydx\frac{dy}{dx}.
    2️⃣ Factor out dydx\frac{dy}{dx} from those terms.
    3️⃣ Divide both sides by the factor multiplying dydx\frac{dy}{dx}.
  • Implicit differentiation is used when one variable is explicitly expressed as a function of the other.
    False
  • Implicit differentiation is useful when the relationship between variables is not easily expressed explicitly
  • Implicit functions require direct differentiation.
    False
  • What is the first step in applying the chain rule to implicit functions?
    Differentiate both sides
  • Solving for dydx\frac{dy}{dx} is the final step in applying the chain rule to implicit functions.

    True
  • Explicit differentiation involves expressing one variable as a direct function of the other.

    True
  • What is the form of an implicit function?
    F(x,y)=F(x, y) =0 0
  • In an explicit function, one variable is expressed directly in terms of the other
  • What is the chain rule formula for differentiating a composite function involving yy?

    ddx[f(y)]=\frac{d}{dx} [f(y)] =f(y)dydx f'(y) \cdot \frac{dy}{dx}
  • The chain rule is used in implicit differentiation to account for terms involving yy.

    True
  • The final step in implicit differentiation is to isolate dydx\frac{dy}{dx}
  • When expressing yy explicitly from the equation x2+x^{2} +y2= y^{2} =25 25, the positive root is \sqrt{25 - x^{2}}
  • Implicit and explicit differentiation methods produce the same derivative for the equation x2+x^{2} +y2= y^{2} =25 25.

    True
  • Steps for implicit differentiation
    1️⃣ Differentiate both sides of the equation with respect to xx.
    2️⃣ Apply the chain rule to terms involving yy.
    3️⃣ Solve for dydx\frac{dy}{dx}.
  • Implicit differentiation is essential for finding derivatives of implicitly defined functions.

    True
  • ddx(y2)=\frac{d}{dx}(y^{2}) =2ydydx 2y \frac{dy}{dx}\frac{dy}{dx}
  • Isolating the term with \frac{dy}{dx}</latex> in 2x+2x +2ydydx= 2y\frac{dy}{dx} =0 0 results in 2ydydx=2y\frac{dy}{dx} =2x - 2x-2x
  • The explicit form of x2+x^{2} +y2= y^{2} =25 25 is y=y =25x2 \sqrt{25 - x^{2}}\sqrt{25}
  • Given the equation x2+x^{2} +y2= y^{2} =25 25, differentiating both sides with respect to xx results in 2x+2x +2ydydx= 2y\frac{dy}{dx} =0 0\frac{dy}{dx}
  • Solving for dydx\frac{dy}{dx} in 8x+8x +18ydydx= 18y\frac{dy}{dx} =0 0 gives dydx=\frac{dy}{dx} =4x9y - \frac{4x}{9y}-
  • Implicit differentiation is the process of differentiating an equation with respect to a variable when both variables are dependent
  • Steps to perform implicit differentiation
    1️⃣ Differentiate both sides of the equation with respect to the independent variable.
    2️⃣ Use the chain rule to differentiate terms where both variables are present.
    3️⃣ Solve for dydx\frac{dy}{dx}.
  • Match the function type with its example:
    Explicit Function ↔️ y=y =x2+ x^{2} +3x+ 3x +1 1
    Implicit Function ↔️ x2+x^{2} +y2= y^{2} =1 1
  • The chain rule is applied differently to implicit and explicit functions.

    True
  • When using the chain rule for terms involving y</latex>, the formula is ddx[f(y)]=\frac{d}{dx} [f(y)] =f(y)dydx f'(y) \cdot \frac{dy}{dx}, where dydx\frac{dy}{dx} is the derivative of y
  • Match the feature with the type of function:
    Relationship is direct ↔️ Explicit function
    Relationship is indirect ↔️ Implicit function
  • What is the general form of an explicit function?
    y=y =f(x) f(x)
  • Implicit functions require implicit differentiation, while explicit functions use direct differentiation.

    True