1.9 Numerical Methods

Cards (39)

  • Exact solutions are used for complex polynomials and transcendental equations.
    False
  • What is the primary goal of using iteration in mathematics?
    Find approximate solutions
  • Fixed point iteration involves applying a function g(x)g(x) to the previous approximation
  • Match the iterative method with its convergence condition:
    Fixed Point Iteration ↔️ g(x)<1|g'(x)| < 1
    Newton-Raphson ↔️ f(x)0f'(x) ≠ 0
    Bisection ↔️ f(a)f(b)<0f(a)f(b) < 0
  • The Newton-Raphson method converges quickly if the initial guess is far from the root.
    False
  • The Newton-Raphson method uses the formula xn+1=x_{n + 1} =xnf(xn)f(xn) x_{n} - \frac{f(x_{n})}{f'(x_{n})} and requires f(x)0f'(x) \neq 0 for convergence.
  • What are the key applications of iteration in numerical methods?
    Solving equations, finding roots, optimization
  • What is the convergence condition for the Newton-Raphson method?
    f(x)0f'(x) \neq 0
  • The convergence condition for the Newton-Raphson method is f(x)0f'(x) ≠ 0
    True
  • Simpson's rule uses parabolic arcs to approximate the integral
  • To approximate \int_{0}^{1} x^{2} dx</latex> using Simpson's rule with n=4, the result is 7/108
  • In Euler's method, the next value of x is calculated using xn+1=x_{n + 1} =xn+ x_{n} +h h
    True
  • Numerical methods are used when finding an exact algebraic solution is too difficult
  • Steps involved in the iterative process to find an approximate solution
    1️⃣ Apply a function or algorithm repeatedly
    2️⃣ Refine the solution until desired accuracy
  • Iterative methods can refine solutions to the desired level of accuracy.
    True
  • Fixed point iteration converges if |g'(x)| < 1 in the region of interest.
    True
  • Steps of the Newton-Raphson method
    1️⃣ Start with an initial guess x0x_{0}
    2️⃣ Apply the iteration formula: xn+1=x_{n + 1} =xnf(xn)f(xn) x_{n} - \frac{f(x_{n})}{f'(x_{n})}
    3️⃣ Repeat until xn+1xn<tolerance|x_{n + 1} - x_{n}| < \text{tolerance}
  • The Newton-Raphson method finds the root of f(x)=f(x) =x32x5 x^{3} - 2x - 5 using an initial guess of x0=x_{0} =2 2.

    True
  • The equation x^{3} - 2x - 5 = 0</latex> has a simple algebraic solution.
    False
  • Steps to find a root using the Newton-Raphson method
    1️⃣ Start with an initial guess x_0
    2️⃣ Apply the iteration formula xn+1=x_{n + 1} =xnf(xn)f(xn) x_{n} - \frac{f(x_{n})}{f'(x_{n})}
    3️⃣ Repeat until xn+1xn<tolerance|x_{n + 1} - x_{n}| < \text{tolerance}
  • For fixed-point iteration to converge, g(x)<1|g'(x)| < 1 in the region of interest.

    True
  • After a few iterations, the root of f(x)=f(x) =x32x5 x^{3} - 2x - 5 using Newton-Raphson method with x0=x_{0} =2 2 is approximately 2.09455
  • Numerical integration approximates the value of an integral using numerical methods
  • Numerical integration is used when analytical techniques are insufficient
    True
  • Euler's method iteratively calculates the next value of y based on the current value and the slope
  • The local truncation error of Euler's method is O(h2)O(h^{2})
    True
  • Why is the Newton-Raphson method used for the equation x32x5=x^{3} - 2x - 5 =0 0?

    No simple algebraic solution
  • Iteration can be used to determine the values of x where a function f(x)f(x) equals zero
  • What is the formula for fixed point iteration?
    xn+1=x_{n + 1} =g(xn) g(x_{n})
  • What does the Newton-Raphson method use to approach the root of a function?
    Derivative of the function
  • What is a condition for the Newton-Raphson method to converge quickly?
    f(x)0f'(x) \neq 0
  • Why are numerical methods used in mathematics?
    Exact solutions are difficult
  • Iteration is used when exact algebraic solutions are impossible.
  • What is the formula for fixed-point iteration?
    xn+1=x_{n + 1} =g(xn) g(x_{n})
  • The Trapezoidal Rule is a numerical method for approximating the value of an integral.

    True
  • The convergence condition for fixed-point iteration is |g'(x)| < 1</latex>

    True
  • The trapezoidal rule has an accuracy of O(h2)O(h^{2})
    True
  • Euler's method solves first-order ordinary differential equations
    True
  • The convergence rate of Euler's method is first-order, meaning it converges as h approaches 0