1.9 Numerical Methods

Cards (100)

  • What are numerical methods used for?
    Approximating solutions
  • Numerical methods provide an approximate solution to mathematical problems.
  • Non-iterative methods provide a direct, one-step solution without iteration.

    True
  • Why are numerical methods useful in mathematics?
    Solve unsolvable problems
  • Iterative methods require less computational effort than non-iterative methods
    False
  • Steps of the bisection method algorithm
    1️⃣ Start with an interval [a, b] containing a root
    2️⃣ Calculate the midpoint c = (a + b) / 2
    3️⃣ If f(a) and f(c) have opposite signs, update b = c
    4️⃣ If f(b) and f(c) have opposite signs, update a = c
    5️⃣ Repeat steps 2-4 until the interval is sufficiently small
  • The update formula for the Newton-Raphson method is x1 = x0 - f(x0) / f'(x0)
  • Numerical methods use algorithms to approximate solutions to mathematical problems.
    True
  • What is the trade-off when using numerical methods?
    Accuracy versus complexity
  • Match the method with its type:
    Newton's method ↔️ Iterative
    Midpoint rule ↔️ Non-iterative
  • Into how many main types can numerical methods be classified?
    Two
  • What is an example of a non-iterative method for integration?
    Midpoint rule
  • The bisection method is faster than other root-finding methods for all problems
    False
  • The Newton-Raphson method requires the ability to calculate the derivative of the function

    True
  • Analytical methods derive an exact, closed-form solution
  • The bisection method starts with an interval where f(a) and f(b) have opposite signs
  • What is one advantage of the bisection method?
    Simplicity
  • The bisection method starts with an interval [a, b] where f(a) and f(b) have opposite signs
  • The bisection method guarantees finding a root if one exists in the initial interval.
    True
  • What is one disadvantage of the bisection method?
    Slow convergence
  • What is the formula to calculate the midpoint in the bisection method?
    c=c =(a+b)/2 (a + b) / 2
  • What is one advantage of the Newton-Raphson method?
    Faster convergence
  • The Newton-Raphson method has faster convergence than the bisection
  • What is the key requirement for the Newton-Raphson method to work effectively?
    Initial guess near the root
  • The Newton-Raphson method is always guaranteed to converge regardless of the initial guess.
    False
  • The fixed point iteration method requires the calculation of derivatives.
    False
  • Order the methods from slowest to fastest convergence rate:
    1️⃣ Bisection
    2️⃣ Fixed-Point Iteration
    3️⃣ Newton-Raphson
  • Root-finding is a key example of a numerical method used to find the roots or zeros of a function
  • How are numerical methods classified based on their approach?
    Iterative and non-iterative
  • What is the bisection method used for?
    Finding roots of a function
  • What is the bisection method used for?
    Finding roots of functions
  • In the bisection method, the midpoint `c` is calculated as `(a + b) / 2
  • What is a key advantage of the bisection method?
    Simplicity
  • For the function `f(x) = x^2 - 4`, the derivative `f'(x) = 2x`.

    True
  • What is a major advantage of the Newton-Raphson method over the bisection method?
    Faster convergence
  • In fixed point iteration, the formula for calculating the next estimate is `x_{n+1} = g(x_n)
  • Match the numerical method with its convergence rate:
    Bisection ↔️ Linear
    Newton-Raphson ↔️ Quadratic
  • In fixed-point iteration, the process stops when the absolute difference between successive estimates is less than a specified tolerance
  • Steps of fixed-point iteration in the correct order:
    1️⃣ Choose an initial guess x0
    2️⃣ Iterate using x_{n+1} = g(x_n)
    3️⃣ Stop when |x_{n+1} - x_n| < tolerance
  • The bisection method is guaranteed to converge regardless of the initial interval.

    True