8.3 Nuclear radius

• The value of r_0</latex> in the nuclear radius formula is approximately 1.2 fm
• Electron diffraction and alpha scattering are the two main methods for measuring nuclear radius.


  True
• A disadvantage of alpha scattering is that alpha particles have a larger size
• The nuclear radius increases linearly with the mass number.

  False
• The nuclear radius increases linearly with the mass number.

  False
• A nucleus with A = 4 (e.g., helium-4) has a smaller radius than a nucleus with A = 16 (e.g., oxygen
• The nuclear radius increases proportionally to the cube root of the mass number.

  True
• The nuclear radius is directly proportional to the nucleon number.

  False
• Match the method with its principle:

  Electron Diffraction ↔️ Electrons scatter off the nucleus

  Alpha Scattering ↔️ Alpha particles scatter off the nucleus
• Both electron diffraction and alpha scattering rely on diffraction patterns or scattering angles to estimate nuclear radius.


  True
• The nuclear radius increases proportionally to the cube root of the mass number
• The formula for nuclear radius is $r =$$r_{0} A^{\frac{1}{3}}$


  True
• The value of $r_{0}$ in the nuclear radius formula is approximately 1.2
• Match the mass number with the corresponding nuclear radius:

  4 ↔️ 1.7 fm

  16 ↔️ 3.4 fm
• The trend of increasing nuclear radius with mass number is due to the addition of more nucleons
• The strong nuclear force overcomes the repulsive electrostatic force between protons.


  True
• What is nuclear radius measured in?

  Femtometres
• What is the formula relating nuclear radius to nucleon number?

  $r =$$r_{0} A^{\frac{1}{3}}$
• What is an advantage of electron diffraction over alpha scattering?

  High precision
• How does nuclear radius change with increasing mass number?

  Increases
• The nuclear radius increases with the mass
• The high density of the nucleus is a consequence of the strong nuclear force