Cards (57)

  • An implicit function is defined by an explicit formula.
    False
  • Match the type of function with its definition:
    Explicit function ↔️ Defined by formula y=y =f(x) f(x)
    Implicit function ↔️ Defined by equation F(x,y)=F(x,y) =0 0
  • The chain rule is applied differently in implicit and explicit differentiation.
    True
  • Grouping terms containing dydx\frac{dy}{dx} is necessary to isolate it.

    True
  • Steps to isolate dydx\frac{dy}{dx} in a differentiated equation

    1️⃣ Differentiate both sides of the equation with respect to xx.
    2️⃣ Group all terms containing dydx\frac{dy}{dx} on one side.
    3️⃣ Factor out dydx\frac{dy}{dx}.
    4️⃣ Divide by the factor to solve for dydx\frac{dy}{dx}.
  • Steps to isolate dydx\frac{dy}{dx} in a differentiated equation

    1️⃣ Differentiate both sides of the equation with respect to xx.
    2️⃣ Group all terms containing dydx\frac{dy}{dx} on one side.
    3️⃣ Factor out dydx\frac{dy}{dx}.
    4️⃣ Divide by the factor to solve for dydx\frac{dy}{dx}.
  • In implicit application problems, x</latex> and yy are related by an equation.

    True
  • An explicit function can be written in the form y=y =f(x) f(x).

    True
  • Grouping terms containing dydx\frac{dy}{dx} is necessary to isolate it.

    True
  • To solve for dydx\frac{dy}{dx}, the final step is to divide
  • What algebraic manipulation is used to differentiate an implicit function?
    Algebraic manipulation
  • The first step in solving related rates problems is to identify variables and their rates.
    True
  • What is the rate at which the water level is rising in the conical tank when it is 5 meters deep?
    12π\frac{1}{2\pi} m/min
  • Implicit functions are differentiated using standard differentiation rules.
    False
  • Steps to isolate dydx\frac{dy}{dx} in a differentiated equation

    1️⃣ Group terms containing dydx\frac{dy}{dx}
    2️⃣ Factor out dydx\frac{dy}{dx}
    3️⃣ Divide both sides to solve for dydx\frac{dy}{dx}
  • Give an example of an implicit function.
    x2+x^{2} +y2= y^{2} =1 1
  • The chain rule is applied to the dependent variable when differentiating implicit functions.

    True
  • The equation x2+x^{2} +y2= y^{2} =1 1 defines an explicit function.

    False
  • What is the result of applying the chain rule to y2y^{2} in the equation x2+x^{2} +y2= y^{2} =1 1?

    2ydydx2y\frac{dy}{dx}
  • Steps to differentiate an implicit function
    1️⃣ Differentiate both sides of the equation
    2️⃣ Isolate the derivative of the dependent variable
  • The chain rule is applied to the independent variable in implicit differentiation.
    False
  • Match the function type with its chain rule application:
    Explicit function ↔️ Chain rule applied directly to y=y =f(x) f(x)
    Implicit function ↔️ Chain rule applied to terms involving yy
  • When applying the chain rule to terms involving yy, it is necessary to treat dydx\frac{dy}{dx} as a separate term
  • In an explicit function, isolating dydx\frac{dy}{dx} involves direct derivation
  • Implicit differentiation is crucial for finding rates of change in problems where the relationship between variables is not explicitly defined
  • Steps to solve related rates problems using implicit differentiation
    1️⃣ Differentiate both sides with respect to time tt.
    2️⃣ Plug in known values.
    3️⃣ Solve for the desired rate of change.
  • Steps to differentiate an implicit function
    1️⃣ Differentiate both sides of the equation with respect to the independent variable.
    2️⃣ Isolate the derivative of the dependent variable (dydx\frac{dy}{dx}) on one side.
  • In explicit functions, dydx\frac{dy}{dx} is found by direct derivation.

    True
  • Steps to differentiate x2+x^{2} +y2= y^{2} =1 1 using implicit differentiation

    1️⃣ Differentiate: 2x+2x +2ydydx= 2y\frac{dy}{dx} =0 0
    2️⃣ Group terms: 2ydydx=2y\frac{dy}{dx} =2x - 2x
    3️⃣ Divide to solve: dydx=\frac{dy}{dx} =xy - \frac{x}{y}
  • Match the equation type with its differentiation method:
    Explicit Function ↔️ Direct derivation
    Implicit Function ↔️ Algebraic manipulation
  • What is the third step in solving related rates problems?
    Differentiate both sides
  • An implicit function is defined by an equation rather than an explicit formula.

    True
  • What is the first step when differentiating an implicit function using the chain rule?
    Differentiate both sides
  • Steps to isolate dydx\frac{dy}{dx} in a differentiated equation

    1️⃣ Differentiate both sides of the equation with respect to xx
    2️⃣ Group terms containing dydx\frac{dy}{dx} on one side
    3️⃣ Factor out dydx\frac{dy}{dx}
    4️⃣ Divide to solve for dydx\frac{dy}{dx}
  • Explicit functions express the dependent variable directly in terms of the independent variable.
  • What is the result of differentiating both sides of x2+x^{2} +y2= y^{2} =1 1?

    2x+2x +2ydydx= 2y\frac{dy}{dx} =0 0
  • What is the first step in differentiating an implicit function?
    Differentiate both sides
  • Factoring out dydx\frac{dy}{dx} is a step in isolating it.

    True
  • What is an implicit function defined by?
    An equation
  • What is an explicit function defined by?
    A formula