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AP Calculus AB
Unit 2: Differentiation: Definition and Fundamental Properties
2.9 The Quotient Rule
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u'(x) represents the derivative of the numerator function u(x).
True
The Quotient Rule formula is dy/dx = (u'v - uv') /
v²
The numerator in the Quotient Rule is denoted as
u(x)
The Quotient Rule is used to find the derivative of a
fractional
function.
Steps to find the derivative of y = (x² + 1) / (x - 2) using the Quotient Rule
1️⃣ Identify u(x) and v(x)
2️⃣ Calculate u'(x) and v'(x)
3️⃣ Apply the Quotient Rule formula
4️⃣ Simplify the expression
What is the simplified derivative of (x² + 1) / (x - 2)?
(x² - 4x - 1) / (x - 2)²
What is the Quotient Rule formula for dy/dx if y = u(x) / v(x)?
(u'v - uv') / v²
What is the derivative of (x² + 1) / (x - 2) after simplification?
(x² - 4x - 1) / (x - 2)²
Match the function with its location in the Quotient Rule:
Numerator ↔️ Above the division line
Denominator ↔️ Below the division line
Plugging the derivatives into the Quotient Rule formula is necessary to find
dy/dx
.
True
In the Quotient Rule,
u(x)
represents the
numerator
function.
What does the Quotient Rule help us differentiate?
Fractions of functions
Steps to apply the Quotient Rule to y = (x² + 1) / (x - 2)
1️⃣ Identify u(x) and v(x)
2️⃣ Calculate u'(x) and v'(x)
3️⃣ Apply the Quotient Rule formula
4️⃣ Simplify the derivative expression
What is the derivative of u(x) = x² + 1?
2x
Match the function with its derivative in the example y = (x² + 1) / (x - 2)
u(x) = x² + 1 ↔️ u'(x) = 2x
v(x) = x - 2 ↔️ v'(x) = 1
What is the derivative of v(x) = x - 2?
1
The derivative of u(x) = x² + 1 is u'(x) = 2x.
True
The Quotient Rule applies when both the numerator and denominator are functions of
x
.
Match the component of the Quotient Rule formula with its description:
u(x) ↔️ Numerator function
v(x) ↔️ Denominator function
u'(x) ↔️ Derivative of u(x)
v'(x) ↔️ Derivative of v(x)
Steps to apply the Quotient Rule to differentiate y = (x² + 1) / (x - 2)
1️⃣ Identify u(x) and v(x)
2️⃣ Find u'(x) and v'(x)
3️⃣ Substitute into the Quotient Rule formula
4️⃣ Simplify the expression
When using the Quotient Rule, the numerator is
u(x)
.
To use the Quotient Rule, you must first differentiate the numerator and denominator
separately
.
After finding the derivatives, the next step is to plug them into the Quotient Rule
formula
.
v'(x) is the derivative of the denominator function in the
Quotient Rule
.
True
u(x) in the Quotient Rule represents the denominator function.
False
The Quotient Rule formula can be written as **dy/dx = (u'v - uv') /
v²
.
In the example, after applying the Quotient Rule, dy/dx is equal to [(2x)(x - 2) - (x² + 1)(1)] /
(x - 2)²
.
The first step in applying the Quotient Rule is to identify the numerator and denominator functions.
True
For the function y = (x² + 1) / (x - 2), the numerator function u(x) is
x² + 1
What is the first step in simplifying a derivative expression after applying the Quotient Rule?
Combine like terms
Common mistakes when applying the Quotient Rule include errors in identifying the numerator or
denominator
The formula for the Quotient Rule is dy/dx = (u'v - uv') /
v²
What is the numerator function in the example y = (x² + 1) / (x - 2)?
x² + 1
The Quotient Rule can only be applied when both the numerator and denominator are functions of
x
.
True
Steps to apply the Quotient Rule to y = (x² + 1) / (x - 2)
1️⃣ Identify u(x) and v(x)
2️⃣ Calculate u'(x) and v'(x)
3️⃣ Apply the Quotient Rule formula
4️⃣ Simplify the derivative expression
The Quotient Rule formula is dy/dx = (u'v - uv') /
v²
What is the derivative of (x² + 1) / (x - 2)?
(x² - 4x - 1) / (x - 2)²
What is the formula for the Quotient Rule?
dy/dx = (u'v - uv') / v²
If u(x) = x² + 1, then u'(x) =
2x
.
True
The Quotient Rule is used to differentiate functions in the form of
fractions
.
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