The electric field is the force per unit charge that would be experienced by an infinitesimal positive test charge placed at any point.
Field strength (E) = Force/Charge
Electric field strength decreases with increasing distance from the source charges.
The greater the charge magnitude, the stronger the electric field intensity.
Electric field strength depends on the magnitude of the electric charge producing the field.
E = V/R Energy = voltage/resistance)
two negative/positive charges make a positive electric force meaning repulsion
One positive and one negative charge means a negative force meaning attraction
Er
1
Electric field strength is known as the potential gradient
Electric field strength = potential/distance
Electric field strength, E = KQ/r^2 where k = 1 /4(pi)(permittivity of free space)
Coulomb’s law? (force exerted on charge due to field)
F = k Qq/r^2 where k = 1 /4(pi)(permittivity of free space)
F = E (energy) x Q
Electric potential energy?
E = kQq / r
Potential = k Q/r (JC-1)
Distance of closestapproach is a way of discovering radius size (not very accurately) and is due to like charges repelling.
At distance of closest approach, the speed of particle is 0. so Ek= Ep (KQq/r)
Parallel plates create a uniform electric field. field Strength constant: force is constant; acceleration of particles is constant.
Equipotentials are equally spaced between parallel plates.
For parallel plates, electric field strength = V/d
If a charged particle enters parallel plates at right angle it’s trajectory will be parabolic so can use suvat as if it were a projectile motion question. Horizontal velocity is constant. vertical acceleration = F/m = EQ/m = VQ/ md (E=V/d) ( F=ma) (F=EQ)
If an object is levitating between parallel plates, the force due to gravity and force due to electric field are equal and opposite. EQ=mg VQ/d = mg Q=mgd/V