redox reactions

Cards (7)

  • what are redox reactions?
    • redox stands for reduction and oxidation reactions
    • redox reactions involve the transfer of e- (electrons)
    • redox reaction is comprised of two half equations:
    • oxidation: loss of electrons (OIL)
    • reactant of this reaction = reductant
  • what are redox reactions?
    • redox stands for reduction and oxidation reactions
    • redox reactions involve the transfer of e- (electrons)
    • redox reaction is comprised of two half equations:
    • oxidation: loss of electrons (OIL)
    • reactant of this reaction = reductant
    • reduction: gain of electrons (RIG)
    • reactant of this reaction = oxidant
  • what are the oxidation number rules?
    1. The oxidation number of an element in its elemental form is zero. 2. The sum of oxidation numbers = overall charge 3. for ions, the oxidation number = charge e.g. Na+ = +1 4. Oxygen usually has an oxidation number of -2, unless it is in a peroxide where it is -1. (H2O2) 5. Hydrogen usually has an oxidation number of +1, unless it is in a hydride where it is -1.
  • how to identify reduction and oxidation reactions?
    • oxidation reaction: reducant's (reactant) oxidation number will increase
    • reduction reaction: oxidant's (reactant) oxidation number will decrease
    • steps:
    • identify conjugate pairs
    • identify oxidation + reduction reaction (oxidation number increase or decrease)
    • label reductant + oxidant
  • what are the steps to write half equation in acidic conditions (acidic is implied unless mentioned otherwise?
    KOHES
    1. key elements (not oxygen or hydrogen)
    2. Oxygen (+H2O)
    3. hydrogen (+H+)
    4. electrons (e-) -> balance charge
    5. states
  • what are the steps to write half equations in basic/alkaline conditions?
    1. KOHES
    2. nH+ -> add nOH- to BOTH SIDES
    3. nH+(aq) + nOH-(aq) -> nH2O(l)
    4. cancel down H2O
  • how to go from full equations to half equations?
    1. identify oxidant and reductant reactants and their conjugates using oxidation numbers (ignore H2O or H+)
    2. balance half equation
    *change in oxidation number = e-