3.3.8 Aldehydes and Ketones

Cards (10)

  • The reduction of pentan-2-one produces pentan-2-ol, the product has no optical activity so it won't rotate plane polarised light. This is because
    > The C=O bond is planar
    > So the hydride nucleophile attacks the C+ equally from above and below
    > This produces equal amounts of the enantiomers
    > Which produces a racemic mixture
  • Aldehydes and Ketones are reduced by the reducing agents [H] to produce alcohols:
    > LiAlH4 in ether
    > NaBH4 aqueous
  • A nucleophile is a species which donates a lone pair of electrons
  • Nucleophilic Addition:
    Hydrogen Cyanide is a very toxic gas and it can lead to death
    Instead a solution of potassium cyanide and dilute sulphuric acid is used to produce HCN
  • The hydride ion from NaBH4 is nucleophile which is attracted to regions of positive charge like the C=O in 2-methyl butanal. Hover 2-methylbut-1-ene the C=C is electron rich so the hydride ion is repelled from C=C in 2-methyl but-1-ene
  • Fractional Distillation
    A) Heat
    B) Anti-bumping granules
    C) thermometer
    D) Water out
    E) Water in
  • Reflux
    A) Water out
    B) Water in
    C) Condenser
    D) anti-bumping granules
    E) ice water
  • Anti-bumping granules prevent explosive boiling, as they provide a large surface area for bubbles to form on.
  • Nucleophilic Addition - Aldehyde/ Ketone
    Condition: aqueous
    Reagent: NaBH4 (Source of :H-)
    Forms: Aldehyde -> 1° alcohol , Ketone-> 2° alcohol
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    Condition: Alcoholic
    Reagent: KCN followed by dilute acid
    Forms: 2-hydroxynitrile
  • Advantage of using KCN or NaCN is that there will be a higher concentration of the CN- ion as these compounds will completely ionise. HCN is a weak acid an will only partially ionise.
    You can use HCN for this reaction but it is a toxic gas that is difficult to contain. KCN/NaCN are still, however, toxic, because of the cyanide ion.