The reduction of pentan-2-one produces pentan-2-ol, the product has no optical activity so it won't rotate planepolarisedlight. This is because
> The C=O bond is planar
> So the hydride nucleophile attacks the C+ equally from above and below
> This produces equal amounts of the enantiomers
> Which produces a racemic mixture
Aldehydes and Ketones are reduced by the reducing agents [H] to produce alcohols:
> LiAlH4 in ether
> NaBH4aqueous
A nucleophile is a species which donates a lone pair of electrons
Nucleophilic Addition:
Hydrogen Cyanide is a very toxic gas and it can lead to death
Instead a solution of potassium cyanide and dilutesulphuric acid is used to produce HCN
The hydride ion from NaBH4 is nucleophile which is attracted to regions of positive charge like the C=O in 2-methyl butanal. Hover 2-methylbut-1-ene the C=C is electron rich so the hydride ion is repelled from C=C in 2-methyl but-1-ene
Fractional Distillation
A) Heat
B) Anti-bumping granules
C) thermometer
D) Water out
E) Water in
Reflux
A) Water out
B) Water in
C) Condenser
D) anti-bumping granules
E) ice water
Anti-bumpinggranules prevent explosiveboiling, as they provide a large surface area for bubbles to form on.
Advantage of using KCN or NaCN is that there will be a higherconcentration of the CN- ion as these compounds will completelyionise. HCN is a weak acid an will only partially ionise.
You can use HCN for this reaction but it is a toxic gas that is difficult to contain. KCN/NaCN are still, however, toxic, because of the cyanide ion.