Equation of a Tangent

• Find the equation of this tangent below (Find the gradient of the radius by using change in y / change in x. Then you should remember that as the tangent is perpendicular to the radius, its gradient will be perpendicular to that of the radius)

  y = - ¾ x + 6 ¼

  
• Find the equation of the tangent below?

  y = - ½ x + 2 ½

  
• Find the equation of the tangent below?

  y = 2 ½ x + 14 ½

  
• Find the equation of the tangent to the circle with the equation x² + y² = 17 at the point (1,p) where p is positive. Hence, find the coordinates where y tangent intercepts the x-axis?

  y = ¼ x + 4 ¼ . Coordinates = ( 17 , 0 )