oxides

Cards (36)

  • oxides of elements may be classified as basic acidic or amphoteric
  • metallic oxides are basic and non-metallic oxides are acidic
  • most metal oxides are basic
  • a basic oxide is one that will react with an acid to form a salt and water
  • some basic oxides are soluble in water and will react to produce an alkaline solution
  • group 1 oxides react in the same way with water
  • amphoteric
    oxides react with acids and bases
  • oxidation states are useful because they allow us to track of electrons in a type of chemical reaction (redox reaction)
  • ch4 is a covalent compound - but we assign oxidation states of -4 for c and +1 for h
  • oxidation states
    • if the compound is ionic the oxidation states are the charges on the ions
    • o is -2 and h is +1 - exceptions
    • assign the most electronegative atom in a molecule/ion a negative oxidation state according to how many electrons it needs to gain a noble gas electron configuration
    • the sum of the oxidation states taking into account signs and number of eaxh atom is equal to the overall charge
    • the oxidation state of atoms in element is zero
    • the maximum possible oxidation state is determined by the number of electrons in the outer shell
  • a difference in electronegativity values between
    atoms of 1.8 or greater gives rise to ionic character.
  • Metal oxides are basic (due to ionic character)
  • Non-metal oxides are acidic (due to covalent
    character)
  • Compounds that are ionic with some covalent
    character or vice versa can be classed as
    amphoteric.
  • Amphoteric oxides show acidic and basic
    properties.
  • As electronegativity values increase from
    left to right across a period, ionic character
    will decrease across a period from left to
    right.
  • Oxides become more ionic down a
    group as electronegativity decreases
    down a group.
  • Ligand Substitution:
    A ligand exchange reaction/substitution reaction
    is a reaction in which one ligand in a complex
    ion is replaced by a stronger ligand from the
    spectrochemical series.
  • To determine the overall charge of a complex you will need to know the oxidation state of the transition metal and the charge(s) of the ligand(s).
  • We see the complimentary colour to the colour that is
    absorbed.
  • Transition metal compounds or complexes are coloured.
  • Why are Sc3+ and Zn2+ compounds colourless?
    sc - empty d sub level
    zn - full d sub level
  • Splitting of the 3d orbitals
    • The electric field produced by a repulsion between ligand’s lone pair of electrons and transition metal electrons, splits the d sub-level into two sub-levels
    • The energy difference between the levels affects how much energy is absorbed when an electron is promoted.
    • The amount of energy governs the colour of light absorbed.
  • In an octahedral complex, two (z2 and x2-y2) go higher and
    three go lower
  • In a tetrahedral complex, three (xy, xz and yz) go higher
    and two go lower
  • The energy difference between the levels affects how
    much energy is absorbed when an electron is promoted.
    The amount of energy governs the colour of light
    absorbed.
  • Transition metals are coloured because:
    • The electric field produced by a ligand’s lone pair of electrons, splits the d sub-level into two sub-level
    • As a photon of light is absorbed a 3d electron from the
    • lower sub-level is excited to the higher sub-level
    • The complimentary colour of the light absorbed is then transmitted
  • What factors might affect the energy
    separation between d-orbitals and hence
    the colour of the complex?
    • Identity of the central metal ion:
    • Charge density of the ligand:
    • Geometry of the complex:
    • Oxidation state of the central metal ion:
  • Spectrochemical series:
    Arranges ligands according to the energy separation, ∆E, between two sets of d-orbitals.
  • Identity of the central metal ion:
    The higher the nuclear charge of a central metal ion, the stronger the coordinate bond between itself and the ligand. As a result there is greater repulsion between 3d
    electrons and the ligands electrons and therefore, greater splitting.
  • Charge density of the ligand:
    A ligand with a greater charge density will produce a larger split in the d-orbitals
  • Geometry of the complex:
    The splitting in energy of the d orbitals depends on the relative orientation of the ligand and the d orbitals
  • Oxidation state of the central metal ion:

    The number of d electrons (i.e. the oxidation state of the metal) will influence the strength of the coordinate bond and the amount of electron repulsion between the d
    electrons and the ligand. The more repulsion, the greater the splitting.
  • oxidation state 

    the degree of oxidation of an atom in terms of counting electrons
  • for trnsition metal the maximum possible oxidation state is given by the sum of the number of electrons in the s and d subshells
  • hydrogen is less electronegative than virtually all the other non-metals