Show that mass is conserved in this reaction: 2Li + F2 -> 2LiF
1)Add up the Ar on the left-hand side of the equation
> 2 x Mr(Li) + 2 x Mr(F) = (2 x 7) + (2 x 19) = 14 + 38 = 52
2) Add up the Ar on the right-hand side
> 2 x Mr(LiF) = 2 x (7 + 19) = 2 x 26 = 52
= The total Mr on the left and right side of the equation equals the same mass, so mass is conserved