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Chem U3
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Cards (182)
In
redox
reactions, something is
oxidised
and something else is
reduced
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Oxidation
is the
loss
of
electrons
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Reduction
is the
gain
of
electrons
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An
oxidising agent
accepts electrons and helps oxidation, becoming
reduced
itself
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A
reducing agent
donates electrons and helps
reduction
, becoming
oxidised
itself
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Rules for assigning oxidation numbers in a compound:
All elements
have an oxidation number of zero
Hydrogen
is
+1
unless with a
Group 1 metal
, then it's
-1
Oxygen
is
-2
(except in
peroxides
when it's
-1
or with
fluorine
when it's
+2
)
Group 1
and
2 elements
are
+1
and +2 respectively
Oxidation numbers in a compound must add up to zero or the ion's charge
The most electronegative element is given the negative oxidation number
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Changes in oxidation number indicate if an element has been
oxidised
or
reduced
:
If the oxidation number
increases
, the element is oxidised
If the oxidation number
decreases
, the element is
reduced
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Equations for redox reactions can be split into
two half-equations
, one for
oxidation
and one for
reduction
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Electrochemical cells have
half-cells
for
oxidation
and
reduction
, joined to form a
complete circuit
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Three types of half-cells:
1.
Metal
/
Metal
ion
2.
Gas
/
Non-metal
ion solution
3.
Solution
of a
metal
in
two
different
oxidation states
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Cells can be represented using
cell diagrams
:
The
conducting metal
of the
left-hand cell
goes
first
Change
of
state
is shown with a
single vertical line
Same physical state
uses
commas
Salt bridge
is represented by a
double vertical line
The more
positive
electrode is on the right-hand side
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Standard electrode potentials
are measured against the
standard hydrogen electrode
, which is taken as
0.0 V
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The standard hydrogen electrode setup:
Platinum
electrode coated with
fine
platinum grains
Standard conditions:
1
atm pressure for
H2
gas,
H+
concentration of
1
mol dm^-3, temperature of
298K
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Using
standard electrode potentials
helps determine
charge
on each
electrode
,
direction
of
electron flow
, and
likelihood
of a
reaction
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The Electrochemical Series orders reducing power of different half-cells:
Most reactive metals have the most negative Eθ
Least reactive metals/most reactive non-metals have the most
positive
Eθ
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The zinc electrode is
negative
and the copper one is
positive
because
electrons
are being
produced
in this reaction
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Zinc metal is being
oxidised
to
zinc
ions
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Copper ions are being
reduced
to
copper
atoms
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Zinc metal is acting as a
reducing agent
because it’s
supplying electrons
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Copper ions are acting as an
oxidising agent
because they are
accepting electrons
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The
red
arrow on the diagram refers to the ions on the
left
, and the
blue
arrow refers to the
reduced
species on the
right
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EMF values for cells must always be
positive
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The EMF of the cell can be calculated using the
standard electrode potentials
of the two half-cells
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For the given cell: Eθ =
+0.34
– (
-0.76
) =
+1.10V
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Eθ values are
positive
or
negative
depending on whether the species has a more
positive
or
negative
potential compared to
hydrogen
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If we compare zinc ions with hydrogen ions, then zinc ions
lose
electrons
more easily
than hydrogen ions
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The
reaction feasibility
can be predicted using
standard electrode potential values
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For a reaction to go ahead, its EMF must be
positive
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The
oxidation half-reaction
is the one with the most
negative
Eθ value
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The
reduction half-reaction
is the one with the most
positive
Eθ value
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When calculating the EMF of a reaction, determine which
half-reaction
is the most
positive
(
reduction
) and which is the most
negative
(
oxidation
)
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In
redox
reactions, if there is a change in
oxidation numbers
, then it is a
redox
reaction
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Redox reactions
are common in
chemistry
and
biology
, seen in processes like
respiration
and
photosynthesis
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Organic chemistry in Unit 4 includes examples of
redox
reactions such as
oxidation
of
alcohols
and
reduction
of
nitriles
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Fuel cells convert
chemical energy
stored in
fuel
into
electrical energy efficiently
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Advantages of fuel cells include producing only
water
and being more
energy efficient
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Disadvantages of fuel cells
include the
flammability
of
hydrogen gas
and
energy loss in hydrogen production from fossil fuels
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You need to construct and combine
ion
/
electron
half-equations for
redox
reactions
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Example
1
:
Chlorine
gas
oxidises iron
(
II
) ions to
iron
(
III
) ions, and chlorine is
reduced
to
chloride
ions
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Example 2:
Manganate
(VII) ions can oxidise hydrogen peroxide to
oxygen gas
, and
manganate
(VII) ions are
reduced
to
manganese
(II) ions
View source
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