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Chem U3
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In
redox
reactions, something is
oxidised
and something else is
reduced
Oxidation
is the
loss
of
electrons
Reduction
is the
gain
of
electrons
An
oxidising agent
accepts electrons and helps oxidation, becoming
reduced
itself
A
reducing agent
donates electrons and helps
reduction
, becoming
oxidised
itself
Rules for assigning oxidation numbers in a compound:
All elements
have an oxidation number of zero
Hydrogen
is
+1
unless with a
Group 1 metal
, then it's
-1
Oxygen
is
-2
(except in
peroxides
when it's
-1
or with
fluorine
when it's
+2
)
Group 1
and
2 elements
are
+1
and +2 respectively
Oxidation numbers in a compound must add up to zero or the ion's charge
The most electronegative element is given the negative oxidation number
Changes in oxidation number indicate if an element has been
oxidised
or
reduced
:
If the oxidation number
increases
, the element is oxidised
If the oxidation number
decreases
, the element is
reduced
Equations for redox reactions can be split into
two half-equations
, one for
oxidation
and one for
reduction
Electrochemical cells have
half-cells
for
oxidation
and
reduction
, joined to form a
complete circuit
Three types of half-cells:
1.
Metal
/
Metal
ion
2.
Gas
/
Non-metal
ion solution
3.
Solution
of a
metal
in
two
different
oxidation states
Cells can be represented using
cell diagrams
:
The
conducting metal
of the
left-hand cell
goes
first
Change
of
state
is shown with a
single vertical line
Same physical state
uses
commas
Salt bridge
is represented by a
double vertical line
The more
positive
electrode is on the right-hand side
Standard electrode potentials
are measured against the
standard hydrogen electrode
, which is taken as
0.0 V
The standard hydrogen electrode setup:
Platinum
electrode coated with
fine
platinum grains
Standard conditions:
1
atm pressure for
H2
gas,
H+
concentration of
1
mol dm^-3, temperature of
298K
Using
standard electrode potentials
helps determine
charge
on each
electrode
,
direction
of
electron flow
, and
likelihood
of a
reaction
The Electrochemical Series orders reducing power of different half-cells:
Most reactive metals have the most negative Eθ
Least reactive metals/most reactive non-metals have the most
positive
Eθ
The zinc electrode is
negative
and the copper one is
positive
because
electrons
are being
produced
in this reaction
Zinc metal is being
oxidised
to
zinc
ions
Copper ions are being
reduced
to
copper
atoms
Zinc metal is acting as a
reducing agent
because it’s
supplying electrons
Copper ions are acting as an
oxidising agent
because they are
accepting electrons
The
red
arrow on the diagram refers to the ions on the
left
, and the
blue
arrow refers to the
reduced
species on the
right
EMF values for cells must always be
positive
The EMF of the cell can be calculated using the
standard electrode potentials
of the two half-cells
For the given cell: Eθ =
+0.34
– (
-0.76
) =
+1.10V
Eθ values are
positive
or
negative
depending on whether the species has a more
positive
or
negative
potential compared to
hydrogen
If we compare zinc ions with hydrogen ions, then zinc ions
lose
electrons
more easily
than hydrogen ions
The
reaction feasibility
can be predicted using
standard electrode potential values
For a reaction to go ahead, its EMF must be
positive
The
oxidation half-reaction
is the one with the most
negative
Eθ value
The
reduction half-reaction
is the one with the most
positive
Eθ value
When calculating the EMF of a reaction, determine which
half-reaction
is the most
positive
(
reduction
) and which is the most
negative
(
oxidation
)
In
redox
reactions, if there is a change in
oxidation numbers
, then it is a
redox
reaction
Redox reactions
are common in
chemistry
and
biology
, seen in processes like
respiration
and
photosynthesis
Organic chemistry in Unit 4 includes examples of
redox
reactions such as
oxidation
of
alcohols
and
reduction
of
nitriles
Fuel cells convert
chemical energy
stored in
fuel
into
electrical energy efficiently
Advantages of fuel cells include producing only
water
and being more
energy efficient
Disadvantages of fuel cells
include the
flammability
of
hydrogen gas
and
energy loss in hydrogen production from fossil fuels
You need to construct and combine
ion
/
electron
half-equations for
redox
reactions
Example
1
:
Chlorine
gas
oxidises iron
(
II
) ions to
iron
(
III
) ions, and chlorine is
reduced
to
chloride
ions
Example 2:
Manganate
(VII) ions can oxidise hydrogen peroxide to
oxygen gas
, and
manganate
(VII) ions are
reduced
to
manganese
(II) ions
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