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Norton's Theorem application
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Cards (18)
What is the purpose of Norton's Theorem?
To simplify
circuit analysis
for current and voltage
What are the components of Norton's equivalent circuit?
Current source
(I_N)
Norton resistance
(R_N)
What is the first step to apply Norton's Theorem?
Identify the
load
across which to find voltage and current
What does Norton's Theorem state about linear circuits?
It simplifies them into a
current source
and resistance
What criteria must a component meet to be considered a load?
It
must be a
specific component
of
interest
Why should the load be detachable from the circuit?
To not affect the
behavior
of other parts
How does the load relate to the rest of the circuit?
It often replaces a complex
network
How do you find the Norton current (I_N)?
By
short-circuiting
the load and calculating current
What are the steps to calculate Norton current (I_N)?
Remove the
load
from the circuit
Connect a
short circuit
across the load terminals
Calculate the current flowing through the short circuit
What is the first action to determine Norton resistance (R_N)?
Deactivate all
independent sources
in the circuit
How do you deactivate voltage sources when finding R_N?
Replace them with
short circuits
(wires)
What should you do with current sources when calculating R_N?
Replace
them with
open
circuits
(removed)
How do you calculate total resistance across load terminals?
Using series and
parallel
resistance formulas
What is the Norton equivalent circuit composed of?
A
current source
and a
parallel resistor
What are the steps to draw the Norton equivalent circuit?
Draw a
current source
(I_N) in the correct direction
Connect a
resistor
(R_N) in parallel with the current source
Indicate the load terminals where the original load was
How do you calculate voltage and current through the load using the Norton equivalent circuit?
Connect the load and use
Ohm's Law
What formulas are used to calculate load current (I_Load) and voltage (V_Load)?
I_Load =
I_N
* (
R_N
/ (R_N +
R_Load
))
V_Load = I_Load * R_Load
Why is the Norton equivalent circuit useful?
It simplifies
calculations
in complex circuits