10.10 Lagrange Error Bound

    Cards (56)

    • What does the Lagrange Error Bound provide an upper limit for?
      Error in Taylor approximation
    • Rn(x)R_{n}(x) represents the remainder or error
    • The value M in the Lagrange Error Bound formula is the maximum value of the (n + 1)th derivative of the function on the interval containing x and a.
    • Steps to calculate the Lagrange Error Bound
      1️⃣ Find the (n + 1)th derivative of the function
      2️⃣ Determine the maximum value M of the derivative on the interval
      3️⃣ Plug the values into the Lagrange Error Bound formula
    • Match the variables in the Lagrange Error Bound formula with their descriptions:
      R_{n}(x) ↔️ Remainder or error
      M ↔️ Maximum value of (n + 1)th derivative
      n ↔️ Degree of the Taylor polynomial
      a ↔️ Center of the Taylor series
    • The Lagrange Error Bound helps ensure that the Taylor polynomial provides a reliable approximation of the function within a specified interval.
    • The remainder term, Rn(x)R_{n}(x), quantifies the difference between the true function value and the approximation provided by the Taylor
    • What formula is used to calculate the remainder term based on the Lagrange Error Bound?
      Rn(x)M(n+1)!xan+1|R_{n}(x)| \leq \frac{M}{(n + 1)!} |x - a|^{n + 1}
    • The value M in the remainder term formula is the maximum value of the (n + 1)th derivative of the function on the interval containing x and a.
    • The remainder term, R_{n}(x)</latex>, represents the error in approximating a function using its Taylor or Maclaurin
    • What does the Lagrange Error Bound estimate the maximum error in?
      Approximating with Taylor polynomial
    • The remainder term, Rn(x)R_{n}(x), quantifies the difference between the true function value and the approximation provided by the nth degree Taylor polynomial
    • What is the formula for the Lagrange Error Bound?
      Rn(x)M(n+1)!xan+1|R_{n}(x)| \leq \frac{M}{(n + 1)!} |x - a|^{n + 1}
    • The value M in the Lagrange Error Bound formula is the maximum value of the (n + 1)th derivative of the function on the interval containing x and a.
    • Rn(x)R_{n}(x) in the Lagrange Error Bound represents the remainder
    • What is the second-degree Taylor polynomial P2(x)P_{2}(x) of f(x)=f(x) =ex e^{x} around a=a =0 0?

      1+1 +x+ x +x22 \frac{x^{2}}{2}
    • The error bound for approximating e^{0.5}</latex> using P2(0.5)P_{2}(0.5) is approximately 0.0343.
    • The maximum error in approximating e0.5e^{0.5} using P2(0.5)P_{2}(0.5) is approximately 0.0343
    • What does the Lagrange Error Bound formula provide an upper limit for?
      The approximation error
    • The Lagrange Error Bound formula is |R_{n}(x)| \leq \frac{M}{(n + 1)!} |x - a|^{n + 1}</latex>.
    • In the Lagrange Error Bound formula, MM is the maximum value of the (n+1)th(n + 1)^{th} derivative on the given interval
    • Match the condition for using the Lagrange Error Bound with its description:
      Function is Differentiable ↔️ f(x)f(x) must be differentiable up to at least n+n +1 1 derivatives
      Maximum Derivative Value Known ↔️ MM, the maximum value of the (n+1)th(n + 1)^{th} derivative, must be known or estimated
      Taylor Polynomial Exists ↔️ f(x)f(x) must have a Taylor polynomial Pn(x)P_{n}(x) centered at aa
    • Steps to calculate the Lagrange Error Bound
      1️⃣ Determine the Taylor polynomial Pn(x)P_{n}(x)
      2️⃣ Find the (n+1)th(n + 1)^{th} derivative of f(x)f(x)
      3️⃣ Calculate or estimate MM
      4️⃣ Apply the Lagrange Error Bound formula
    • The third derivative of f(x)=f(x) =ex e^{x} is exe^{x}.
    • In the example of approximating exe^{x}, the maximum value of the third derivative MM at x=x =0.5 0.5 is approximately 1.649
    • The maximum error in approximating e^{0.5}</latex> using the second-degree Taylor polynomial is approximately 0.0343.
    • What does the Lagrange Error Bound estimate the maximum error for?
      Taylor polynomial approximation
    • Match the component of the Lagrange Error Bound with its description:
      Rn(x)R_{n}(x) ↔️ Remainder (error)
      MM ↔️ Maximum value of f(n+1)(x)f^{(n + 1)}(x)
      nn ↔️ Degree of Taylor polynomial
      aa ↔️ Center of Taylor series
    • The Lagrange Error Bound formula is Rn(x)M(n+1)!xan+1|R_{n}(x)| \leq \frac{M}{(n + 1)!} |x - a|^{n + 1}, where nn represents the degree of the Taylor polynomial
    • What does the remainder term R_{n}(x)</latex> represent in Taylor polynomial approximation?
      The approximation error
    • The maximum value of the (n+1)th(n + 1)^{th} derivative in the Lagrange Error Bound is denoted by MM.
    • What is the fourth derivative of exe^{x}?

      exe^{x}
    • The remainder term for approximating exe^{x} with a third-degree Maclaurin polynomial atx = 0.1</latex> is approximately 0.0000046
    • The third-degree Maclaurin polynomial provides a highly accurate approximation of e0.1e^{0.1}.
    • Match the component of the Lagrange Error Bound with its description:
      Rn(x)R_{n}(x) ↔️ Remainder (error)
      MM ↔️ Maximum value of f(n+1)(x)f^{(n + 1)}(x)
      nn ↔️ Degree of Taylor polynomial
      aa ↔️ Center of Taylor series
    • What is the maximum value of the (n+1)th(n + 1)^{th} derivative in the Lagrange Error Bound formula?

      MM
    • The Lagrange Error Bound formula is Rn(x)M(n+1)!xan+1|R_{n}(x)| \leq \frac{M}{(n + 1)!} |x - a|^{n + 1}, where aa represents the center of the Taylor series
    • What is the formula for the Lagrange Error Bound?
      Rn(x)M(n+1)!xan+1|R_{n}(x)| \leq \frac{M}{(n + 1)!} |x - a|^{n + 1}
    • The remainder in the Lagrange Error Bound formula is denoted by R_{n}(x)
    • In the Lagrange Error Bound, M represents the maximum value of the (n+1)th(n + 1)^{th} derivative on the interval containing xx and a</latex>.
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