8.15 Arc Length of a Curve

    Cards (48)

    • Arc length is the distance along a curve between two points
    • Arc length allows for the accurate measurement of complex curves using integration.
    • The length of a curve between x=x =a a and x=x =b b can be calculated using the arc length formula, which involves integrating the square root of 1+1 +(dydx)2 \left(\frac{dy}{dx}\right)^{2} with respect to xx from aa to bb.a
    • What is the expression for the differential arc length dsds in terms of dxdx and dydx\frac{dy}{dx}?

      ds=ds =1+(dydx)2dx \sqrt{1 + \left(\frac{dy}{dx}\right)^{2}} dx
    • The arc length formula includes the derivative of the function with respect to xx.
    • Arc length is the distance along a curve between two points
    • The arc length of the curve y=y =x2 x^{2} from x=x =0 0 to x = 2</latex> can be found using integration.
    • What is the formula for calculating arc length in Cartesian coordinates?
      L=L =ab1+(dydx)2dx \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^{2}} dx
    • Steps to calculate the arc length of y=y =x2 x^{2} from x=x =0 0 to x =2</latex>

      1️⃣ Find dydx\frac{dy}{dx}: dydx=\frac{dy}{dx} =2x 2x
      2️⃣ Substitute into the arc length formula: L=L =021+(2x)2dx \int_{0}^{2} \sqrt{1 + (2x)^{2}} dx
      3️⃣ Evaluate the integral: L4.6468L \approx 4.6468
    • To apply the arc length formula, we first need to find dydx\frac{dy}{dx} for the given function
    • What does dydx\frac{dy}{dx} represent?

      The derivative of yy
    • The arc length formula is L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^{2}} dx</latex>, where dydx\frac{dy}{dx} is the derivative of the function.
    • To apply the arc length formula, we first need to find dydx\frac{dy}{dx} for the given function.
    • What is the first step in applying the arc length formula?
      Find dydx\frac{dy}{dx}
    • After finding dydx\frac{dy}{dx}, we substitute it into the arc length formula.
    • The arc length formula requires the derivative dydx\frac{dy}{dx} to be squared.
    • What is the derivative of y=y =x3 x^{3} with respect to xx?

      3x^{2}</latex>
    • For y=y =x3 x^{3}, the arc length formula becomes L=L =011+(3x2)2dx \int_{0}^{1} \sqrt{1 + (3x^{2})^{2}} dx, where (3x2)2(3x^{2})^{2} is the square of the derivative.
    • What is the derivative of y=y =x3 x^{3} with respect to xx?

      3x23x^{2}
    • Steps involved in applying the arc length formula
      1️⃣ Find the derivative dydx\frac{dy}{dx}
      2️⃣ Substitute into the arc length formula
      3️⃣ Evaluate the resulting integral
    • The arc length formula can be applied to various functions by following the same steps.
    • What are two common integration techniques used in arc length problems?
      U-substitution and trigonometric substitution
    • U-substitution simplifies the integral when the integrand contains a function and its derivative.
    • To find the arc length of y=y =x2 x^{2} from x=x =0 0 to x=x =2 2, we can use U-substitution.
    • What substitution should be used for \int \sqrt{1 + (2x)^{2}} dx</latex>?
      u=u =2x 2x
    • To solve arc length problems involving integration, we typically use U-substitution or trigonometric substitution to evaluate the integrals
    • When the integrand contains a function and its derivative (or a constant multiple of the derivative), U-substitution simplifies the integral
    • Steps to find the arc length of y=y =x2 x^{2} from x=x =0 0 to x=x =2 2 using U-substitution

      1️⃣ Find dydx\frac{dy}{dx}: 2x2x
      2️⃣ Substitute into the arc length formula: L=L =021+(2x)2dx \int_{0}^{2} \sqrt{1 + (2x)^{2}} dx
      3️⃣ Let u=u =2x 2x, then du=du =2dx 2 dx
      4️⃣ Rewrite the integral: L=L =121+u2du \frac{1}{2} \int \sqrt{1 + u^{2}} du
      5️⃣ Use a standard integral formula
      6️⃣ Substitute back u=u =2x 2x and evaluate from x=x =0 0 to x=x =2 2
    • U-substitution is effective when the integrand contains a function and its derivative.
    • When the integrand contains square roots of quadratic expressions, trigonometric substitution is an effective method
    • Trigonometric substitution is used when the integrand contains expressions like a2x2\sqrt{a^{2} - x^{2}}, \sqrt{a^{2} + x^{2}}, or x2a2\sqrt{x^{2} - a^{2}}.
    • Arc length is significant in calculus because it allows us to accurately measure the length of complex curves
    • What is the formula for arc length in Cartesian coordinates?
      L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^{2}} dx</latex>
    • Steps to find the arc length of y=y =x2 x^{2} from x=x =0 0 to x=x =2 2 using the arc length formula

      1️⃣ Find dydx\frac{dy}{dx}: 2x2x
      2️⃣ Substitute into the arc length formula: L=L =021+(2x)2dx \int_{0}^{2} \sqrt{1 + (2x)^{2}} dx
      3️⃣ Evaluate the integral
    • The arc length formula is L = \int_{a}^{b} \sqrt{1 + \left(\frac{dy}{dx}\right)^{2}} dx</latex>, where LL is the arc length, aa and bb are the limits of integration
    • What does dydx\frac{dy}{dx} represent in the arc length formula?

      Derivative of y with respect to x
    • To apply the arc length formula, we first need to find dydx\frac{dy}{dx} for the given function
    • Steps to find the arc length of y=y =x3 x^{3} from x=x =0 0 to x=x =1 1
      1️⃣ Find dydx\frac{dy}{dx}: 3x23x^{2}
      2️⃣ Substitute into the arc length formula: L=L =011+(3x2)2dx \int_{0}^{1} \sqrt{1 + (3x^{2})^{2}} dx
      3️⃣ Evaluate the integral
    • U-substitution and trigonometric substitution are commonly used to evaluate arc length integrals.
    • What is the first step in finding the arc length of y=y =sinx \sin x from x=x =0 0 to x=x =π2 \frac{\pi}{2}?

      dydx=\frac{dy}{dx} =cosx \cos x
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