Cards (54)

  • What is the Quotient Rule used for?
    Differentiating quotients of functions
  • The Quotient Rule formula is \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>, where y=y =u(x)v(x) \frac{u(x)}{v(x)} and dydx\frac{dy}{dx} is the derivative
  • The Quotient Rule involves subtracting the product of the numerator's derivative and the denominator from the product of the numerator and the denominator's derivative.
  • Steps to apply the Quotient Rule
    1️⃣ Identify u(x)u(x) and v(x)v(x)
    2️⃣ Compute u(x)u'(x) and v(x)v'(x)
    3️⃣ Substitute into the Quotient Rule formula
    4️⃣ Simplify the result
  • What is the formula for the Quotient Rule?
    dydx=\frac{dy}{dx} =u(x)v(x)u(x)v(x)[v(x)]2 \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}
  • The Quotient Rule is used to differentiate functions that are the quotient of two other functions.
  • What is the formula for the Sum/Difference Rule?
    ddx[u(x)±v(x)]=\frac{d}{dx}[u(x) \pm v(x)] =u(x)±v(x) u'(x) \pm v'(x)
  • Match each differentiation rule with its formula:
    Sum/Difference Rule ↔️ ddx[u(x)±v(x)]=\frac{d}{dx}[u(x) \pm v(x)] =u(x)±v(x) u'(x) \pm v'(x)
    Product Rule ↔️ ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x)
  • What is the formula for the Quotient Rule?
    \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>
  • The Quotient Rule is used to differentiate functions that are the quotient of two other functions.
  • What is the formula for the Product Rule?
    ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x)
  • The Quotient Rule formula includes subtracting the product of the numerator's derivative and the denominator from the product of the numerator and the denominator's derivative.
  • What is the Quotient Rule formula?
    \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>
  • Match each differentiation rule with its formula:
    Sum/Difference Rule ↔️ ddx[u(x)±v(x)]=\frac{d}{dx}[u(x) \pm v(x)] =u(x)±v(x) u'(x) \pm v'(x)
    Product Rule ↔️ ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x)
    Quotient Rule ↔️ ddx[u(x)v(x)]=\frac{d}{dx}\left[\frac{u(x)}{v(x)}\right] =u(x)v(x)u(x)v(x)[v(x)]2 \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}
  • What is the general formula for the Quotient Rule when y=y =u(x)v(x) \frac{u(x)}{v(x)}?

    dydx=\frac{dy}{dx} =u(x)v(x)u(x)v(x)[v(x)]2 \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}
  • For the function y = \frac{x^{2}}{x + 1}</latex>, the derivative using the Quotient Rule is \frac{x^{2} + 2x}{(x + 1)^{2}}.
  • What is the Quotient Rule used to differentiate?
    The quotient of two functions
  • The Quotient Rule states that if y=y =u(x)v(x) \frac{u(x)}{v(x)}, then \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>, where dydx\frac{dy}{dx} is the derivative
  • For the function y=y =x2x+1 \frac{x^{2}}{x + 1}, the derivative using the Quotient Rule is \frac{x^{2} + 2x}{(x + 1)^{2}}.
  • What type of functions is the Quotient Rule used to differentiate?
    Fractions of functions
  • For y = \frac{x^{2}}{x + 1}</latex>, the derivative dydx\frac{dy}{dx} is \frac{x^{2} + 2x}{(x + 1)^{2}}
  • The Quotient Rule formula is dydx=\frac{dy}{dx} = \frac{u'(x)v(x) + u(x)v'(x)}{[v(x)]^{2}}.

    False
  • What is the formula for differentiating a sum of functions using the Sum/Difference Rule?
    \frac{d}{dx}[u(x) \pm v(x)] = u'(x) \pm v'(x)</latex>
  • The Product Rule states that ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x). An example of its application is 2x \sin x + x^{2} \cos x
  • Match the differentiation rule with its formula:
    Sum/Difference Rule ↔️ ddx[u(x)±v(x)]=\frac{d}{dx}[u(x) \pm v(x)] =u(x)±v(x) u'(x) \pm v'(x)
    Product Rule ↔️ ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x)
    Quotient Rule ↔️ u(x)v(x)u(x)v(x)[v(x)]2\frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}
  • What is an example of a derivative calculated using the Quotient Rule?
    \frac{2x(x + 1) - x^{2}}{(x + 1)^{2}}</latex>
  • For y=y =x2x+1 \frac{x^{2}}{x + 1}, the derivative dydx\frac{dy}{dx} using the Quotient Rule is \frac{x^{2} + 2x}{(x + 1)^{2}}
  • The Quotient Rule is used to differentiate functions of the form y = \frac{u(x)}{v(x)}
  • What is the formula for the Quotient Rule?
    \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>
  • What is the derivative of 2x+2x +3 3 using the Sum/Difference Rule?

    22
  • The Product Rule states that ddx[u(x)v(x)]=\frac{d}{dx}[u(x)v(x)] =u(x)v(x)+ u'(x)v(x) +u(x)v(x) u(x)v'(x), where u(x)u'(x) is the derivative of u(x)
  • Give an example where the Quotient Rule is used to find the derivative of \frac{x^{2}}{x + 1}</latex>
    \frac{x^{2} + 2x}{(x + 1)^{2}}
  • The Quotient Rule is used to differentiate functions that are the sum of two other functions.
    False
  • The Quotient Rule is used to differentiate functions that are the quotient of two other functions.
  • What does u(x)u'(x) represent in the Quotient Rule?

    Derivative of the numerator
  • Steps to apply the Quotient Rule:
    1️⃣ Identify u(x)u(x) and v(x)v(x).
    2️⃣ Compute u(x)u'(x) and v(x)v'(x).
    3️⃣ Use the formula: ddx(uv)=\frac{d}{dx}\left(\frac{u}{v}\right) =uvuvv2 \frac{u'v - uv'}{v^{2}}.
    4️⃣ Simplify the resulting expression.
  • The derivative of v(x)=v(x) =x+ x +1 1 is v(x)=v'(x) =2 2.

    False
  • The Quotient Rule states that if y=y =u(x)v(x) \frac{u(x)}{v(x)}, then \frac{dy}{dx} = \frac{u'(x)v(x) - u(x)v'(x)}{[v(x)]^{2}}</latex>, where v(x)v'(x) is the derivative of the denominator
  • What is the derivative of the denominator in the Quotient Rule called?
    v(x)v'(x)
  • To apply the Quotient Rule, we use the formula \frac{d}{dx}\left(\frac{u}{v}\right) = \frac{u'v - uv'}{v^{2}}