Explain the trend on this graph:
- Increased nuclear charge
- Decreased atomic radius
- Same electron shielding
which means more energy is needed to remove the first electron
Dips at Al b/c: outer electron is in a 3p orbital, higher energy than 3s orbital —> less energy needed to remove electron
Dips at S b/c: one 3p orbital contains two electrons —> repulsion between paired electrons -> less energy needed to remove one