Chemistry formulas/equations

Cards (23)

  • Empirical formula?
    (given mass of element/given total mass of compound) x 100 = %
    %/atomic mass of element = moles
    moles/smallest # of moles found = empirical formula unit
  • Molecular formula?
    Given total mass/molecular mass of empirical formula = scale factor
    Scale factor x empirical formula = molecular formula
  • Molar concentration (in mol/dm3)
    moles of solute/dm3 of solvent (C=n/V)
    if no volume given, assume V=1
  • How to identify the number of ions in a molecule
    First, apply the swap and drop rule for charges
    (Take for example Mg(NO3)2 -> swap+drop -> Mg^2+ NO3^- (bcs Mg's initial denominator was 1 and NO3's denominator was 2)
    Then, add the absolute value of the charges together for the # of ions
    (|2|+|-1| = 3 ions)
    Lastly, multiple it by Avogadro's number
    (3 x (6.02x10^23))
  • Moles
    grams/atomic mass
  • Concentration of a newly diluted solution
    C1V1=C2V2
  • Percentage yield
    (actual yield/theoretical yield) x 100
  • 2 ways to find limiting reactants
    a ) Find the theoretical yield of product created by each reactant value. The one with the smallest yield is limiting reactant
    b ) Convert grams to moles and divide by their coefficient. Then compare the resulting values as the smaller one is the limiting reactant
  • Volume of a gas product
    Use limiting reactant to find moles of product then plug into V=nRT/P
  • Find theoretical yield
    Indentify for which product the actual yield is given. Use the limiting reactant to multiply it with the (moles of the product/moles of the LR) and then with its molecular mass
  • Ionization energy
    E=hv where E is energy in Joules, v is frequency in (s^-1) and h is Plank's constant
    C=vl where C is the speed of light, v is frequency in (s^-1). and l is wavelength in meters
  • Paper chromatography Retention factor (Rf)

    distance moved by solute up the paper/distance moved by solvent up the paper
  • Percentage by mass of element in a compound
    Multiply the atomic mass of element with its mole coefficient then divide that amount with the compound's molecular mass. This amount is then multiplied by a 100 to find the value of percentage composition
  • Atoms of an element in a compound given total amount of compound in moles
    Identify coefficient of element and multiply it to the total amount of compound in moles. Then, multiply it with Avogadro's constant (6.02x10^23)
  • Equation for nth electron ionization
    X^((n-1)+) -> X^(n+) + e^-
  • Equation for nth electron affinity
    X^((n-1)-) + e^(-) -> X^(n-)
  • Combustion analysis is finding composition of hydrocarbon from combustion data
    1. take mass of CO2/H20 divided by its molecular mass and then multiplied by its coefficient in the molecule (ex. H20 holds 2 hydrogen, CO2 holds 1 carbon)
    2. divide by smallest amount found then multiple both to get whole
    numbers (if needed) = molecular formula
  • 0.5 x 2=1
    0.333... x 3 =1
    0.25 x 4 =1
    0.2 x 5 =1
    0.4 x 5 =2
  • The total potential difference (E[total]) of the electrochemical cell is calculated as follows: E[cathode] - E[anode]
  • 0.0821 is R for dm3 atm/mol K units
  • A is mass number
  • Z is atomic number
  • X is actual element