OZ 3

    Cards (57)

    • Halo alkanes
      Alkanes with one or more halogen attached to them
    • Naming examples
      • Trifluoroethane
      • 2-chlorobutane
      • 1-bromo-1,1-dichloroethane
    • The slides used in the video are available for purchase by clicking on the link in the description box
    • The video is presented by Chris Harris from a website called Luriecheaters.com
    • Halo alkanes have polar bonds and are attacked by nucleophiles due to the electronegativity of halogens pulling electrons towards themselves
    • The video provides an overview of the halo alkanes part of the ozone story topic in Salters
    • The video is on halo alkanes for OCR be Salters
    • The slides are dedicated to the Salters specification and map the specification points listed in the syllabus from Salters
    • Naming halo alkanes
      Find the longest carbon chain, name the halogens as prefixes in alphabetical order with numbers to state their positions on the carbon chain
    • Boiling points of halo alkanes increase as you go down the group due to the increase in the number of electrons in the halogen, leading to stronger intermolecular forces
    • Nucleophile
      A substance that is an electron pair donor
    • Nucleophilic substitution reaction
      Occurs when alkanes react with hydroxide ions under warm aqueous sodium hydroxide conditions
    • Reaction with water
      Occurs via nucleophilic substitution under heat and base conditions
    • Nucleophiles
      • Ammonia, water, hydroxide ions
    • Compounds with polar bonds are attacked by nucleophiles
    • Nucleophilic substitution mechanism
      1. Nucleophile attacks the Delta positive carbon, replacing the halogen
      2. Formation of a bond between the nucleophile and the carbon
      3. Heterolytic break of the bond with electrons moving to the halogen
      4. Formation of an alcohol and a halide
    • Formation of an intermediate in the reaction with water
      1. Water attacks the Delta positive carbon, replacing the halogen
      2. Formation of an intermediate with a positive charge on oxygen
      3. Breakage of the O-H bond to form alcohol and H+ ion
      4. Interaction of H+ ion with chloride ion to balance charges
    • Formation of alcohol from C
      Formation of alcohol from C, production of H+ ion, interaction with chloride ion, ensuring charges are balanced
    • Evidence for reactivity based on reacting haloalkanes with silver nitrate
    • Haloalkanes become more reactive as we go down the group
    • Reactivity of carbon-halogen bonds
      • CI bond
      • CB bond
      • CI bond
    • Reactions with CI bond are the most reactive compared to reactions with CF bond
    • Nucleophilic substitution with ammonia
      Reaction with ammonia, conditions needed: heat, ethanolic ammonia, excess ammonia, attack on Delta positive carbon, formation of intermediate, addition of NH3 onto the molecule, formation of ammonium ion
    • Bond strength or bond enthalpy determines the reactivity of haloalkanes, not bond polarity
    • Formation of silver iodide, silver bromide, and silver chloride based on bond strength
    • The next strongest bond after the strongest one is bronze chloride
    • Bond fishing involves two types: homolytic and heterolytic
    • Propagation in free radical chain reactions involves radicals reacting with non-radicals to create new radicals, continuing the chain reaction
    • Homolytic bond fishing
      The bond breaks and the pair of electrons in the bond are shared equally to form two radicals
    • The set of rules for free radical chain reactions can be used to make haloalkanes like bromomethane
    • Heterolytic bond fishing
      The bond breaks but the electrons are distributed equally to form two different ions
    • Termination in free radical chain reactions occurs when two radicals collide to form a non-radical molecule, ending the reaction
    • Bronze chloride forms the slowest and has the strongest bond density between the car and the chlorine
    • Initiation in free radical chain reactions involves breaking bonds homolytically using UV light to produce highly reactive radicals
    • Initiation in making bromomethane involves breaking the Br-Br bond using UV light to produce highly reactive radicals
    • Free radical chain reactions
      1. Initiation: Radicals are produced using UV light to break bonds homolytically
      2. Propagation: Radicals react with non-radicals to create new radicals
      3. Termination: Two radicals collide to form a non-radical molecule, ending the reaction
    • Radical produced in the second propagation stage is always the radical used in the first stage as a reactant
    • CFCs, chlorofluorocarbons, break down ozone in the stratosphere
    • The frequency of UV radiation determines the ability to break CFC bonds
    • CFCs are broken down by UV radiation in the stratosphere, forming radicals like fluorine and alkane radicals
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