The capacitance C of a capacitor is the charged stored per unit potential difference:
C = Q/V
1 farad is a large capacitance so it is common to see capacitors labelled in microfarads.
A simple capacitor consists of two parallel metal plates opposite each other with a gap between them.
The energy stored in a charge capacitor can be calculated using:
E = 1/2 QV = 1/2 CV^2 = 1/2 Q^2 /c
The energy stored by a charged capacitor is equal to the area under the chance against p.d graph or the p.d against charge graph.
The energy supplied to charge up a capacitor is:
E = QV
The energy stored by the capacitor is half of E =QV because the rest of energy is lost to the resistance of the circuit and the internal resistance of the power supply.
the charge stored on the plates of a capacitor can be increased by inserting a dielectric between the plates.
the relative permittivity of a dielectric is the ratio of charge stored with the dielectric to the charge stored without a dielectric.
E = C/C0 = Q/Q0 = E/E0
Dielectrics increase the capacitance of a capacitor by:
dielectrics contain polar molecules that align themselves with the electric field between the plates.
this causes an electric field that partially cancels the electric field caused by the charges against the plate.
This reduces p.d across the capacitor meaning more charge can be stored per volt.
Parallel plate capacitor:
for a parallel plate capacitor with a dielectric between plates the capacitance is :
C = A e0 er / d
Graphs of current against time for the discharging of a capacitor show an exponential decay.
The area under the current-time graph is equal to the charge that has flowed off the capacitor. The gradient of the tangent of the charge-time graph at any point is equal to the current at that time.
The time constant for a capacitor discharge circuit is :
time constant = RC
RC is the time taken for the charge , current and p.d to fall to 1/e of its original value.
5RC is a good approximation of the time taken to fully discharge a capacitor.
the time constant is equal to -1/gradient of the graphs of ln V,Q,I against time.
The half-life of a capacitor discharge circuit is the time take for the charge , current and p.d to fall to halve.
T (1/2) = 0.69RC
Relative permittivity is the ratio of charge stored with the dielectric between plates compared to the charge stored without the dielectric.
The area underneath a graph of charge against p.d represents the energy stored by the capacitor
The time constant is the time it takes for the charge in a capacitor to fall to 37% of the initial values. A capacitor is seen as fully discharged after 5 time constants.
To derive 37%:
start with the Q = Q0 x e ^ (-t /rc)
T = RC after one time constant
Q=Q0 x e^ -1
e^-1 is 0.37 hence 37%
The half life of a capacitor is 0.69RC
How does a capacitor charge:
electrons move from negative to positive around a circuit.
The electrons are deposited on plate A making them negatively charged.
Electrons travel from plate B to the positive terminal of the battery , generating a positive charge on the plate.
Electrons build up on plate A and an equal amount of electrons are removed from plate B , creating a potential difference across the plates.
When p.d across plate = p.d source the capacitor is charged.
movement of electrons across a capacitor when it discharges across a resistor:
Electrons move in an opposite direction compared to when the capacitor was charging up.
Charge on one plate A decreases as it loses electrons , plate B gains electrons neutralizing them.
P.d decreases exponentially across the plates.
Two factors that affect time taken for capacitor to charge or discharge:
the capacitance - this affects the amount of charge that can be stored by the capacitors at any given p.d across it.
The resistance of the circuit and how quickly it flows , hence how quickly the capacitor charges/ discharges.