A balanced chemical equation is one in which the number of atoms of each element is equal on both sides of the equation. Equations must be balanced at all times. The amount of hydrogens on both sides should be an even number whenever H2O is present on one side. If there are 4 hydrogen atoms, then 8 hydrogen atoms are present. If there are 7 hydrogen atoms, then 14 hydrogen atoms, indicating that all the numbers are even. There must be an even number in front of HCl on the reactant side. As a result, there will be an even amount of chlorine atoms. However, the quantity of chlorine atoms in the product is unusual. Let's alter it to the simplest even number we can think of, which is 2. Since the number of K atoms in 2 KCl = 2, we have to put 2 in front of KMnO4 for balancing K atoms. In 2 KMnO4, there are 2 K, 2 Mn, and 8 O. So, add these numbers in front of K, Mn, and O. If there are 8 H2O on the product side, there should be 16 H (8 x 2) on the reactants side as well. Now the only unbalanced one is Chlorine. On the left-hand side, there are 16 Cl. On the right-hand side, there are 2 Cl in 2 KCl + 4 Cl in 2 MnCl2, making a total of 6(2 + 4). So, 10 more Cl atoms are to be accounted for. Place 5 in front of 2 Cl2 to make it 10 (5 x 2)