Alkenes

Cards (20)

  • The Cahn-Ingold-Prelog priority rules are used to deduce the full IUPAC name
  • In the Cahn-Ingold-Prelog rules, an atom with a higher atomic number takes priority.
  • Steps to determine the priority groups using the Cahn-Ingold-Prelog rules
    1️⃣ Consider the groups attached to the left-hand carbon of the C=C bond
    2️⃣ Consider the groups attached to the right-hand carbon of the C=C bond
    3️⃣ Determine the higher priority groups on each carbon
    4️⃣ Check if the higher priority groups are on the same side of the C=C bond
    5️⃣ Assign the Z or E isomer
  • If the higher priority groups are on the same side of the C=C bond, it is the Z-isomer.
  • Match the type of reaction with its description:
    Addition reaction ↔️ A small molecule is added across the C=C bond
    Electrophilic addition ↔️ Reaction with an electron pair acceptor
  • Electrophiles are attracted to the high electron density of the C=C bond in alkenes.
  • A curly arrow shows the movement of a pair of electrons.
  • What is the observation when bromine reacts with ethene?
    Orange to colourless
  • In the reaction of bromine with ethene, bromine acts as the electrophile.
  • Bromine is used to test for the presence of a C=C group in a molecule.
  • Hydrogen halides (HX) react with alkenes via electrophilic addition.
  • What are the two possible products when propene reacts with hydrogen chloride?
    1-chloropropane and 2-chloropropane
  • In hydrogen halides, the hydrogen atom is always δ+ due to the permanent dipole.
  • When ethene reacts with concentrated sulfuric acid, the product is ethane hydrogensulfate.
  • What is the definition of hydrolysis?
    The breaking of a bond using water
  • The hydration of alkenes to form alcohols requires steam and a phosphoric acid catalyst.
  • Order the stability of carbocations from most stable to least stable
    1️⃣ Tertiary (3°)
    2️⃣ Secondary (2°)
    3️⃣ Primary (1°)
  • Unsymmetric alkenes produce two different organic products upon electrophilic addition.
  • In the addition of HBr to propene, which carbocation is more stable?
    2° carbocation
  • The major product in electrophilic addition to unsymmetrical alkenes is formed via the more stable carbocation.