This reaction releases sulphur dioxide, so the experiment should be carried out in a well-ventilated place
These 2 chemicals are both clear solutions. They react together to form a yellow precipitate of sulfur
2. Start by adding a set volume of dilute sodium thiosulfate to a conical flask
3. Place the flask on a piece of paper with a black cross drawn on it. Add some dilute HCl to the flask and start the stopwatch
4. Now watch the black cross disappear through the cloudy sulfur and time how long it takes to go
5. The reaction can be repeated with solutions of either reactant at different concentrations. The depth of the liquid must be kept the same each time
6. These results show the effect of increasing the concentration of HCl on the rate of reaction, when added to an excess of sodium thiosulfate
7. The higher the concentration, the quicker the reaction and therefore the less time it takes for the mark to disappear
8. One disadvantage about this reaction is that it doesn't give a set of graphs. All you get is a set of readings of how long it took until the mark disappeared for each concentration
9. Although you can draw a graph of concentration against 1/time which will give you an approximate rate