carbs

Cards (33)

  • monosaccharides
    • A source of energy in metabolic processes
    • have the general formula Cn(H2O)n, where n varies from 3 to 8
    • Aldose: A monosaccharide containing an aldehyde group
    • Ketose: A monosaccharide containing a ketone group
    A) aldose
    B) ketose
  • naming monosaccharides
    • prefix: number of carbons in molecule
    • suffix: ose, indicates that it is a carbohydrate
    A) triose
  • silver mirror test
    • used to detect the presence of aldehydes
    • based on the reduction of silver ions to silver metal, which forms the mirror
    • Tollens' reagent selectively oxidises aldehydes but not ketones
    • conclusion: if an aldehyde is present, silver forms because aldehyde is oxidised to carboxyl group ALLOWING Ag+ in Tollens' reagent to reduce to Ag solid.
    • on the other hand, if ketones were present, nothing would occur as it cannot undergo oxidation, preventing Ag+ to reduce.
  • carbohydrates
    • carbohydrate = hydrated carbon atom (has H & OH's)
    • small carbohydrates = sugars (name ends in "ose")
    • monosaccharide names: triose, tetrose, pentose, hexose
    • these monosacch. will either have ketone or aldehyde functional group ("aldose" or "ketose")
    A) aldohexose
    B) ketopentose
  • fischer projection
    • a way to represent 3D molecules in a 2D format (usually with carbohydrates and amino acids)
    • emphasizing the stereochemistry of chiral centers
    A) wedge
    B) dash
  • D vs L sugars
    1. look at the SECOND LAST carbon
    2. if the -OH points right, it's ( D )
    3. if the -OH points left, it's ( L )
    helps differentiate between enantiomers of sugar molecules
    A) d
    B) l
  • monosaccharides
    • exist in an equilibrium between linear or cyclic compounds (cyclic more common)
    • they form cycles by an intramolecular hemiacetal formation
    • hemiacetal forms because an alcohol attacks an aldehyde or ketone (ie. intramolecular cycling)
  • monosaccharides - link with number of stereoisomers
    1. starts with 2 glyceraldehydes (D and L, one chiral centre)
    2. then 4 aldotetroses (2D and 2L, two chiral centres)
    3. then 8 aldopentoses (4D and 4L, three chiral centres)
    4. then 16 aldohexoses (8D and 8L, four chiral centres)
    note: image only shows D, not L
  • D glucose
    • aldehyde group
    • hydroxyl group: right, left, right, right (going down)
  • glucose and fructose
    • glucose is an aldose
    • fructose is a ketose
    A) fructose
  • glucose and galactose
    • epimer: diastereomers that differ only at ONE chiral centre (diast. differ at at least one chiral centre)
    • galactose is the C-4 epimer of glucose
    A) galactose
    B) glucose
  • cyclic glucose
    1. react with acid (H+) to activate aldehyde (turns to -COOH)
    2. -OH group on 5th carbon will attack the carboxyl group
    3. this breaks the pi bond (sp2),
    4. the molecule bends into hexagon. If -OH group on right, it points down, if -OH group on left, it points up
    5. the OH, H and CH2OH will rotate to be in correct orientation
    6. when -OH alings with -COOH, it will form a or b glucose
  • chain to cyclic glucose
    A) CH2OH
    B) H
    C) H
  • hamiacetals
    • Aldehydes and ketones react with alcohols to form hemiacetals
    • this leads to a molecule with an (-OH) group and an ether group on the same carbon atom
  • Haworth projection
    • this is a way of showing 3D cyclic molecules as 2D, helping to understand the stereochemistry
    • linear form = less stable, cyclic form = more stable
  • anomers
    • definition: a pair of stereoisomers, usually sugars, that differ due to the configuration of the -OH group
    • anomeric carbon: the new stereocentre resulting from cyclic hemiacetal formation
    A) b
    B) a
    C) cis
    D) trans
  • infixes
    • 6 hemiacetal ring has -pyran- infix (hexagon)
    • 5 hemiacetal ring has -furan- infix (pentagon)
    A) pyran
    B) furan
  • chair conformation
    • for furanoeses (5): planar representation
    • for pyranoses (6): chair conformation
    • axial position: when an atom or group is bonded vertically up or down (usually small atoms - H)
    • equatorial position: when an atom or group is bonded diagonally (usually larger groups - OH)
    A) equatorial
  • b-D-GLUCOSE (haworth projection --> chair conformation)
    1. horizontal timelapse, with O in top right (hemiacetal bond)
    2. label the carbon numbers. 1 is the anomeric carbon, 6 is the CH2OH
    3. order atoms/groups in axial or equatorial position (using rule)
    4. a-glucose = -OH group in axial position on 1st carbon
    5. b-glucose = -OH group in equatorial position on 1st carbon
    A) equatorial
    B) chair
    C) haworth
  • why is b-glucose more common?
    • the equatorial position is always more stable
    • more stable by minimising steric hindrance
    • basically means the repulsions of electrons in b-glucose are more stable than a-glucose
    • this is because the -OH groups are all in equatorial positions, hence more stable and more common
  • mutorotation
    • where a solution of a cyclic compound (eg. glucose) changes its rotation due to the equilibrium between its α and β anomers (due to the ring opening and closing)
    • b-D-glucose rotates plane polarised light by +18.7 degrees
    • a-D-glucose rotates it by +112 degrees
    • if b-glucose is put in water, its rotation changes from 18.7 to 52.7, and a will decrease to 52.7, telling us that both forms exist but more B anomer
  • disaccharides - glycoside formation
    • -OH of the anomeric carbon is replaced by –OR (acetal formation)
    • the OH on glucose and OH on methanol forms an acetal group (not ether) connected by glycoside bond
    • cyclic acetals are NOT in equilibrium, so they do not undergo mutarotation (cannot change between a/b forms)
    A) glycoside
    B) anomeric
  • disaccharides
    • sugars are alcohols so they can bind to each other
    • a-1,4'-glycoside bond
    • "a-1" means the start of the bond is from the 1st carbon of alpha molecule
    • "4'-glycoside bond" means the bond connects from the 4th carbon on the other molecule
  • more examples
    A) b
    B) a
  • N-glycosides
    • The anomeric carbon of a cyclic hemiacetal also reacts with the N-H group of amine to form an N-glycoside
    A) anomeric
    B) glycoside
  • sucrose disaccharide
    • fructose + glucose
    • here, the glycoside bond is a & b because it's a-glucose + b-fructose
    A) a
    B) 1
  • Polysaccharides
    • the red squiggle means its a chain, so the molecule continues
    • cellulose is made of only b-glucose
    A) 4
    B) 1
    C) starch
  • cellulose
    • provides structure in plants due to its rigid structure
    • has a linear chain connected by strong hydrogen bonding
    • the D-glucose units are joined by b-1,4 links
  • starch
    • fully digestible (unlike cellulose) and only present in plants
    • eg. beans, wheat, rice, potatoes
    • D-glucose is joined by a-1,4 links
  • starch - amylose
    • amylose makes up 20% of starch
    • amylose coils into helices and forms a linear chain
    • contains only a-1,4 links
    • soluble in hot water
  • starch - amylopectin
    • amylopectin makes up 80% of starch
    • amylopectin forms a branched structure (higher surface area)
    • contains a-1,4 and a-1,6 links
    • insoluble in water
  • glycogen
    • stores energy in animals in the liver and muscles
    • similar to amylopectin in being a long polymer of D-glucose with the same type of links
    • same as amylopectin but with MORE branches
    A) plants
    B) animals
  • mutarotation (commonly tested)
    • applies only when in a SOLUTION
    • when glucose dissolves in water, it forms an equilibrium of a and b forms because the cyclic ring opens and closes
    • optical rotation: the way light bends when it passes through solution
    • a and b glucose bend light in different angles, helping scientists
    • eg. 1) b-glucose put in water, 2) -O- bond goes back to -OH (6th carbon) and -COOH (1st carbon) 3) carboxyl group flips 180 4) reform -O- bond but now it's a-glucose