energy

Cards (48)

  • Enthalpy of atomisation
    The enthalpy change when 1 mole of gaseous atoms is formed from the element in its standard state
  • Enthalpy of atomisation
    • Na (s) → Na(g) [atH = +148 kJ mol-1]
    • ½ O2 (g) → O (g) [atH = +249 kJ mol-1]
  • Enthalpy of sublimation
    The enthalpy change for a solid metal turning to gaseous atoms, numerically the same as the enthalpy of atomisation
  • Enthalpy of sublimation
    • Na (s) → Na(g) [subH = +148 kJ mol-1]
  • First ionisation enthalpy
    The enthalpy change required to remove 1 mole of electrons from 1 mole of gaseous atoms to form 1 mole of gaseous ions with a +1 charge
  • Second ionisation enthalpy
    The enthalpy change to remove 1 mole of electrons from one mole of gaseous 1+ ions to produces one mole of gaseous 2+ ions
  • First electron affinity
    The enthalpy change that occurs when 1 mole of gaseous atoms gain 1 mole of electrons to form 1 mole of gaseous ions with a –1 charge
  • First electron affinity
    • O (g) + e- → O- (g) [eaH] = -141.1 kJ mol-1
  • Second electron affinity
    The enthalpy change when one mole of gaseous 1- ions gains one electron per ion to produce gaseous 2- ions
  • Second electron affinity
    • O – (g) + e- → O2- (g) [eaH = +798 kJ mol-1]
  • Lattice Enthalpy (LEH)

    The standard enthalpy change when 1 mole of an ionic crystal lattice is formed from its constituent ions in gaseous form
  • Lattice Enthalpy
    • Na+ (g) + Cl- (g) → NaCl (s) [LEH = -787 kJ mol-1]
  • Enthalpy of Hydration (hydH)
    The enthalpy change when one mole of gaseous ions become aqueous ions
  • Enthalpy of Hydration
    • X+ (g) + aq → X+ (aq) [For Li+ hydH = -519 kJ mol-1]
    • X- (g) + aq → X- (aq) [For F- hydH = -506 kJ mol-1]
  • Enthalpy of solution (solH)
    The standard enthalpy change when one mole of an ionic solid dissolves in a large enough amount of water
  • Enthalpy of solution
    • NaCl (s) + aq → Na+ (aq) + Cl-(aq) [solH]
  • Enthalpy of formation (fH)
    The standard enthalpy change when 1 mole of a compound is formed from its elements under standard conditions
  • Enthalpy of formation
    • Na (s) + ½Cl2 (g) → NaCl (s) [fH = - 411.2 kJ mol-1]
  • Lattice Enthalpy
    • Can be used as a measure of ionic bond strength
    • Cannot be determined directly, calculated indirectly using Born-Haber cycle
  • Born-Haber cycle

    Applies Hess's law to calculate lattice enthalpy indirectly using other enthalpy changes
  • Factors affecting lattice enthalpy
    • Sizes of the ions (larger ions = less negative lattice enthalpy)
    • Charges on the ions (higher charges = more negative lattice enthalpy)
  • Trends in lattice enthalpies
  • Entropy (S)
    A description of the number of ways atoms can share quanta of energy. Higher disorder = higher entropy
  • Substances with higher entropy
  • Change in entropy (ΔS)

    • Positive if there is an increase in disorder (e.g. solid/liquid to gas, increase in number of molecules)
    • Negative if there is a decrease in disorder (e.g. gas to solid/liquid, decrease in number of molecules)
  • Calculating ΔS
    ΔS = Σ S°products - Σ S°reactants
  • Gibbs free energy change (ΔG)
    Combines the effects of enthalpy and entropy into one value
  • Elements in their standard states do not have zero entropy. Only perfect crystals at absolute zero (T = 0 K) will have zero entropy
  • Standard entropy change (ΔS°)

    Σ S°products - Σ S°reactants
  • Unit of entropy
    J K-1 mol-1
  • At 0K substances have zero entropy. There is no disorder as particles are stationary
  • Activation Energy (EA)

    The energy barrier that must be overcome for a reaction to occur
  • ΔS° = 558.1 J K-1 mol-1 = 558 J K-1 mol-1 (3 S.F.) for the reaction: 2Fe2O3 (s) + 3C (s) 4Fe (s) + 3CO2 (g)
  • Gibbs Free Energy Change (ΔG)

    A term that combines the effect of enthalpy and entropy into one number
  • Relationship between ΔG, ΔH and ΔS
    ΔG = ΔH - TΔS
  • For any spontaneous change, ΔG will be negative
  • A reaction that has increasing entropy (+ve ΔS) and is exothermic (-ve ΔH) will make ΔG be negative and will always be feasible
  • For the reaction Al2O3(s) + 3C(s) → 2Al(s) + 3CO(g): ΔH° = +1336 kJ mol-1, ΔS° = +581 J K-1 mol-1, ΔG = +1163 kJ mol-1
  • The reaction N2(g) + O2(g) → 2NO(g) will be feasible at temperatures above 7200K
  • The temperature for methane to melt is 91K