Ratio of the density of a substance to the density of a reference substance
Dilutions
The desired molarity solutions are often prepared from concentrated stock solutions by adding water.
Moles of solute before dilution = Moles of solute after dilution
M1 x V1 = M2 x V2
The ice floats on top of the water
Salad oil is less dense than vinegar
Density
Gas = low density
Liquids: close to 1 g/cm3, 1 g/mL
Metals: various heavy densities
Density Example 1
Given: Gas fills a volume of 1200 mL and has a mass of 1.60 g
Calculate: Density of the gas
Density = mass / volume = 1.60 g / 1200 mL = 0.00133 g/mL
Density Example 2
Given: A cube of pure silver measures 2.0 cm on each side, density of silver is 10.5 g/cm3
Calculate: Mass of the cube
Density Example 3
Given: Density of air is 1.25 x 10-3 g/cm3, room dimensions are 5.00 m x 4.00 m x 2.2 m
Calculate: Mass of air in the room
Dilution
A process where the concentration of a solution is lowered by adding solvent to the solution without adding more solute
Making a Dilution
Remove sample from concentrated solution
Add solvent to make dilute solution
Shake to mix
Dilution Example
Given: 94.0% (g/100 g) H2SO4 with density 1.831 g/mL, need to prepare 1 L of 0.100 M solution
Calculate: Volume (mL) of 94.0% H2SO4 required
Molarity of 94.0% H2SO4 solution = 17.5 M
Use formula: M1V1 = M2V2 to calculate V1 = 5.7 mL
Dilution Example 2
Given: 98.0% (wt/wt) H2SO4 with concentration 18.0 M, need to dilute to 0.1 M H2SO4 in 1.00 L
Calculate: Volume (mL) of 98.0% H2SO4 required
Density of 98.0% H2SO4 needs to be calculated first
Titration
A technique where the analyte reacts with a known concentration titrant (standard solution) from a burette. The volume of titrant required to just completely react with the analyte is measured.
Titration Principles
Write reaction equation and find ratio of reactants
Calculate moles of titrant from volume and concentration
Use conversion factor to find moles of analyte: molA = molB * a/b
Titration Example
Given: 0.4671 g sample containing sodium bicarbonate, titrated with 0.1067 M HCl, requiring 40.72 mL
Reaction: NaHCO3 + HCl → NaCl + H2CO3
Calculate: Percent sodium bicarbonate in the sample
Primary Standard
A highly pure material used to prepare a standard solution by dissolving an accurately weighed quantity and diluting to an accurately known volume
Secondary Standard
A solution standardized by titrating a primary standard, less accurate than a primary standard due to titration errors
Requirements of a Primary Standard
100.00% pure
Stable to drying and at room temperature, always dried before weighing
Readily available
High formula weight to reduce weighing error
Types of Volumetric Methods
Acid-Base (neutralization reaction)
Precipitation (titrant forms insoluble product with analyte)
Complexometric (titrant is a complexing agent forming water-soluble complex with analyte)
Oxidation-Reduction (titration of an oxidizing agent with a reducing agent)
Yield of Chemical Reactions
Theoretical yield (calculated from equation) is the calculated quantity of product
Actual yield (from experiment) is the amount actually obtained