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SEM I DEGREE
CHM3052
CHAPTER 3
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Ways to measure
Mass
Volume
Counting pieces
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Measure mass
In
grams
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Measure
volume
In liters
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Count pieces
In
moles
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Atomic, Molecular and Formula Weight
Gram-atomic
weight is the weight of a specified number of atoms of that element
Gram-molecular
weight is the sum of the atomic weights of the atoms that make up a compound
Gram-formula
weight or
molar mass
is a more accurate description for substances that exist as ionic compounds
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Moles
Moles (g/mol) =
grams
/
formula weight
ONE mol of substances =
atomic
/molecule/
formula weight
of the substances
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Molarity
Molarity
(M) is the concentration of a solution expressed as the number of
moles
of solute per liter of solution
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Normality
Normality (N or eq/L) =
mass
(g) / (
eq.wt
x V (L))
Equivalent wt (g/eq) =
molecular
wt /
no.reacting
unit
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Reaction types and their equivalent units
Precipitation
: Charge of cation or anion
Acid-base
: Number of H+ donated by acid or accepted by base
Complexation
: Number of electron accepted by metal or donated by ligand
Oxidation-reduction
: Number of electron released by reducing agent or accepted by oxidizing agent
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Molality
A
one-molal
solution contains one mole per 1000 g of
solvent
Molality
is commonly used in physicochemical measurements because it is not
temperature
dependent as molar and normal
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Common Units for Reporting Concentration
Wt/wt
,
Wt/vol
, Vol/vol, ppt, mg/g, g/kg, mg/mL, g/L, ppm, mg/kg, µg/g, mg/L, µg/mL, µL/L, nL/mL, ppb, µg/kg, ng/g, µg/L, ng/mL, nL/L, pL/mL, %
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Density
Amount of
mass
present in a given
volume
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Specific Gravity
Ratio of the
density
of a
substance
to the density of a reference substance
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Dilutions
The desired molarity solutions are often prepared from
concentrated stock solutions
by adding
water.
Moles
of solute before dilution =
Moles
of solute after dilution
M1
x V1 =
M2
x V2
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The
ice
floats on top of the
water
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Salad oil
is less dense than
vinegar
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Density
Gas
=
low
density
Liquids
: close to
1
g/cm3, 1 g/mL
Metals
: various
heavy
densities
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Density Example 1
Given
: Gas fills a volume of 1200 mL and has a mass of 1.60 g
Calculate
:
Density
of the gas
Density = mass / volume =
1.60
g /
1200
mL = 0.00133 g/mL
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Density Example
2
Given: A cube of pure silver measures
2.0
cm on each side, density of silver is
10.5
g/cm3
Calculate:
Mass
of the cube
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Density Example 3
Given: Density of air is
1.25
x 10-3 g/cm3, room dimensions are
5.00
m x 4.00 m x 2.2 m
Calculate:
Mass
of air in the room
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Dilution
A process where the
concentration
of a solution is lowered by adding
solvent
to the solution without adding more solute
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Making a Dilution
Remove sample from
concentrated
solution
Add solvent to make
dilute
solution
Shake
to mix
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Dilution Example
Given:
94.0
% (g/100 g) H2SO4 with density
1.831
g/mL, need to prepare 1 L of 0.100 M solution
Calculate: Volume (mL) of 94.0% H2SO4 required
Molarity of 94.0% H2SO4 solution =
17.5
M
Use formula:
M1V1
= M2V2 to calculate V1 =
5.7
mL
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Dilution Example 2
Given: 98.0% (wt/wt) H2SO4 with concentration 18.0 M, need to
dilute
to
0.1
M H2SO4 in 1.00 L
Calculate: Volume (mL) of
98.0
% H2SO4 required
Density of
98.0
% H2SO4 needs to be calculated first
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Titration
A technique where the analyte reacts with a known
concentration
titrant (standard solution) from a burette. The volume of titrant required to just completely react with the
analyte
is measured.
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Titration
Principles
Write
reaction equation
and find ratio of reactants
Calculate
moles
of titrant from volume and concentration
Use
conversion factor
to find
moles
of analyte: molA = molB * a/b
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Titration
Example
Given: 0.4671 g sample containing
sodium bicarbonate
,
titrated
with 0.1067 M HCl, requiring 40.72 mL
Reaction: NaHCO3 +
HCl
→ NaCl +
H2CO3
Calculate: Percent
sodium bicarbonate
in the sample
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Primary Standard
A highly pure material used to prepare a standard solution by dissolving an
accurately weighed
quantity and diluting to an
accurately known volume
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Secondary Standard
A
solution
standardized by titrating a primary standard, less accurate than a primary standard due to
titration errors
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Requirements of a Primary Standard
100.00
% pure
Stable to
drying
and at room temperature, always
dried
before weighing
Readily available
High
formula
weight to reduce
weighing
error
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Types of Volumetric Methods
Acid-Base
(neutralization reaction)
Precipitation
(titrant forms insoluble product with analyte)
Complexometric
(titrant is a complexing agent forming water-soluble complex with analyte)
Oxidation-Reduction
(titration of an oxidizing agent with a reducing agent)
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Yield of Chemical Reactions
Theoretical yield
(
calculated
from equation) is the calculated quantity of product
Actual yield
(from
experiment
) is the amount actually obtained
Percent
yield
= (actual yield / theoretical yield) *
100
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Limiting Reactant
The reactant which runs out first, determines the amount of product
Excess Reactant
is added to ensure the limiting reactant is completely used up
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Finding
Limiting
Reactant
Calculate the
amount
of product produced by each reactant
The reactant that produces the lesser amount of product is the
limiting
reactant
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Calculating Excess Reactant
Calculate
moles
of
limiting
reactant
Calculate
moles
of
excess
reactant that reacts
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