Amount of substance

Cards (74)

  • Mole
    The amount of substance in grams that has the same number of particles as there are atoms in 12 grams of carbon-12
  • Avogadro's Number
    There are 6.022 x 10^23 atoms in 12 grams of carbon-12
  • One mole of any specified entity contains 6.022 x 10^23 of that entity
  • Equations used for most calculations at A-level
    • For pure solids, liquids and gases
    • For gases: PV = nRT
    • For solutions
  • Relative atomic mass
    The average mass of one atom compared to one twelfth of the mass of one atom of carbon-12
  • Relative molecular mass
    The average mass of a molecule compared to one twelfth of the mass of one atom of carbon-12
  • Using Equation 1
    1. Calculate the number of moles of CuSO4 in 35.0g of CuSO4
    2. Calculate the number of moles in 75.0mg of CaSO4.2H2O
  • Avogadro's Constant
    6.022 x 10^23
  • Calculating number of atoms/ions/molecules

    1. Calculate the number of atoms of tin in a 6.00 g sample of tin metal
    2. Calculate the number of chloride ions in a 25.0 cm3 of a solution of magnesium chloride of concentration 0.400 mol dm-3
    3. Calculate the number of molecules of ethanol in a 0.500 dm3 of ethanol (CH3CH2OH) liquid
  • Calculating density
    Calculate the density of gold in a bar measuring 10 cm by 20 cm by 50 cm with 980 mol of pure gold
  • Empirical formula
    The simplest ratio of atoms of each element in the compound
  • Molecular formula
    The actual number of atoms of each element in the compound
  • Determining empirical formula
    Calculate the empirical formula for a compound that contains 1.82g of K, 5.93g of I and 2.24g of O
  • Heating in a crucible
    1. Weigh an empty clean dry crucible and lid
    2. Add 2g of hydrated calcium sulfate to the crucible and weigh again
    3. Heat strongly with a Bunsen for a couple of minutes
    4. Allow to cool
    5. Weigh the crucible and contents again
    6. Heat crucible again and reweigh until you reach a constant mass
  • Determining water of crystallisation
    1. Calculate the value of the integer x in ZnSO4.xH2O
    2. Calculate the value of x in Na2SO4 . xH2O
  • Concentration of solutions
    • Unit of concentration: mol dm-3 or M
    • Unit of volume: dm3
  • Converting volumes
    1. cm3 to dm3: divide by 1000
    2. cm3 to m3: divide by 1,000,000
    3. dm3 to m3: divide by 1,000
  • Calculating concentration of solution
    Calculate the concentration of solution made by dissolving 5.00 g of Na2CO3 in 250 cm3 water
  • Ration
    mol dm-3 or M
  • Unit of volume
    dm3
  • Converting volumes
    1. cm3 to dm3 ÷ 1000
    2. cm3 to m3 ÷ 1000 000
    3. dm3 to m3 ÷ 1000
  • Moles
    mass/Mr
  • Concentration
    moles/volume
  • cm3
    Equivalent to a cube 1cm x 1cm x 1cm
  • dm3
    Equivalent to a cube 10cm x 10cm x 10cm = 1000 cm3
  • m3
    Equivalent to a cube 100cm x 100cm x 100cm = 1000000 cm3
  • Solution
    Mixture formed when a solute dissolves in a solvent
  • Molar concentration
    Calculated by dividing the amount in moles of the solute by the volume of the solution, measured in dm3
  • Converting concentration mol dm-3 to g dm-3
    Multiply by Mr of the substance
  • Mass concentration
    Concentration of a solution measured in terms of mass of solute per volume of solution, unit g dm-3
  • Ions dissociating
    Soluble ionic solids dissolve in water and dissociate into separate ions
  • Making a solution

    Weigh sample, transfer to beaker, add solvent, pour into volumetric flask, make up to mark
  • Diluting a solution

    Pipette original solution into volumetric flask, make up to mark with solvent
  • Calculating dilutions
    New diluted concentration = original concentration x original volume / new diluted volume
  • Ideal gas equation
    PV = nRT
  • Using a gas syringe
    Measure volume, temperature and pressure to calculate moles of gas
  • Reacting volumes of gas
    Equal volumes of gases under same conditions contain equal moles, volumes can be calculated by simple ratio
  • Equal volumes of any gases
    Measured under the same conditions of temperature and pressure, contain equal numbers of molecules (or atoms if the gas is monatomic)
  • 1 mole of any gas
    At room pressure (1atm) and room temperature 25oC will have the volume of 24dm3
  • Reacting volumes of gas
    Volumes of gases reacting in a balanced equation can be calculated by simple ratio