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A level chemistry
Physical II
Acids and bases
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Cards (134)
What is a Bronsted-Lowry acid?
A
substance
that can donate a proton
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What is a Bronsted-Lowry base?
A substance that can
accept
a
proton
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What happens when HCl reacts with water?
It forms
H3O+
and Cl-
ions
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What is the relationship between acids and their conjugate bases?
Each
acid
is
linked
to a
conjugate
base
Conjugate base forms after the acid donates a
proton
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What is the formula for calculating pH?
pH = -
log
[H+]
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How do strong acids behave in solution?
They
completely dissociate
in solution
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What is the pH of a 0.1 mol dm-3 HCl solution?
pH =
1.00
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How do you find [H+] from pH?
[H+] = 10^-ph
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What is the concentration of HCl with a pH of 1.35?
[H+] = 0.045
mol dm-3
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What is the ionic product for water (Kw)?
Kw = [
H
+][OH-]
At
25°C
, Kw =
1
x
10
^-14 mol2dm-6
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Why is pure water neutral?
[
H+
]=[
OH-
] in pure water
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How do you calculate [H+] in neutral water using Kw?
[H+] =
√Kw
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What is the pH of pure water at 25°C?
pH =
7
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How does temperature affect the pH of pure water?
Higher
temperature
lowers
pH
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What is the pH of water at 50°C with Kw = 5.476 x 10^-14
pH =
6.6
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How do strong bases behave in solution?
They
completely dissociate
into
ions
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How do you calculate pH from [OH-] for strong bases?
Use
Kw
to find [
H+
]
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What is the pH of 0.1 mol dm-3 NaOH?
pH =
13.00
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What is the dissociation expression for weak acids?
HA
+ H2O ⇌
H3O
+ +
A-
Ka = [
H+
][A-]/[HA]
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What is the Ka for ethanoic acid?
1.7 x 10^-5 mol dm-3
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What does a larger Ka indicate?
Stronger
acid
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What is the pH of 0.01 mol dm-3 ethanoic acid?
pH =
3.38
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How do you find [H+] from pH for weak acids?
[H+] = √(
Ka
×
[HA]initial
)
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What is the concentration of propanoic acid with a pH of 3.52?
[
CH3CH2CO2H
] = 6.75 x
10<sup>-3</sup>
mol dm<sup>-3</sup>
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What is the relationship between pKa and Ka?
pKa
=
-log
Ka
Ka
=
10
^
-pka
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What are the steps for calculating pH in neutralization reactions?
Calculate
moles
of
acid
and
base
Determine which is in
excess
Calculate new concentration of excess ions
Use
pH formula
to find pH
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How do you calculate pH for strong acid and strong base neutralizations?
Use excess
moles
to find [
H
+]
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What is the pH of the mixture from 45cm3 of 1.0 mol dm-3 HCl and 30cm3 of 0.65 mol dm-3 NaOH?
pH =
0.47
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What is the pH of the mixture from 15cm3 of 0.5 mol dm-3 HCl and 35cm3 of 0.55 mol dm-3 NaOH?
pH =
13.37
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What is the pH of the mixture from 15cm3 of 0.5 mol dm-3 HCl and 35cm3 of 0.45 mol dm-3 Ba(OH)2?
pH =
13.68
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What
is the pH of the mixture from 35cm3 of 0.5 mol dm-3 H2SO4 and 30cm3 of 0.55 mol dm-3 NaOH?
pH = 0.55
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What is the difference between strong diprotic acids and bases in neutralization calculations?
Strong diprotic acids release two
protons
Strong diprotic bases
release two hydroxide ions
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What is the formula for calculating moles of a substance?
Moles =
concentration
x
volume
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What is the pH of a solution with
[
H
+
]
=
[H^+] =
[
H
+
]
=
2.08
×
1
0
−
14
mol dm
−
3
2.08 \times 10^{-14} \text{ mol dm}^{-3}
2.08
×
1
0
−
14
mol dm
−
3
?
13.68
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How do you calculate the concentration of
[
O
H
−
]
[OH^-]
[
O
H
−
]
in a mixture?
[
O
H
−
]
=
[OH^-] =
[
O
H
−
]
=
m
o
l
e
s
e
x
c
e
s
s
O
H
−
t
o
t
a
l
v
o
l
u
m
e
(
d
m
3
)
\frac{moles \, excess \, OH^-}{total \, volume \, (dm^3)}
t
o
t
a
l
v
o
l
u
m
e
(
d
m
3
)
m
o
l
es
e
x
cess
O
H
−
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What is the relationship between moles of
H
+
H^+
H
+
and
O
H
−
OH^-
O
H
−
in a neutralization reaction?
They react in a
1:1 ratio
to form water
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How do you calculate the moles of
H
2
S
O
4
H_2SO_4
H
2
S
O
4
in a reaction?
Moles =
concentration
x
volume
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What is the pH of a solution with
[
H
+
]
=
[H^+] =
[
H
+
]
=
0.28
mol dm
−
3
0.28 \text{ mol dm}^{-3}
0.28
mol dm
−
3
?
0.55
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What are the steps to calculate the pH of a weak acid and strong base neutralization?
Calculate
moles
of acid and base.
Determine which is in
excess
.
Calculate new concentration of excess acid or base.
Use
p
H
=
pH =
p
H
=
−
log
[
H
+
]
-\log[H^+]
−
lo
g
[
H
+
]
or
p
O
H
=
pOH =
pO
H
=
−
log
[
O
H
−
]
-\log[OH^-]
−
lo
g
[
O
H
−
]
as needed.
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What is the formula for calculating the pH of a weak acid at half equivalence?
pH =
pKa
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