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Mechanics
Forces
Connected Particles
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Cards (15)
If you have two objects, A and B, with A on top of B, and B on the floor, what are the forces involved?
A's
weight pushing down on
B
Normal reaction of
B
pushing on
A
B's
weight pushing
down
on the floor
Same normal reaction as
2.
of
A
pushing down on
B
Normal reaction of the floor pushing
up
on
B
Normal reaction
: An object at rest on a surface exerts a force on the surface. The reaction force
acts at
right angles
to the surface
When a particle of mass m is resting on the floor, what is the normal reaction from the floor equal to?
mg
What does particle A experience when particle B is resting on top of it?
The normal reaction from the weight of
B
NOT the weight of
B
Particles moving forward typically have a
driving force
and incur
friction
When one particle is pulling another forward, it experiences
tension
from the connection
If a particle is being pulled forward,
tension
pulls it forward, and
friction
resists the motion
A stationery pulley with weights on either side, experiences
tension
on both sides and an equal normal reaction going
up
Both weights on either side of a stationery pulley experience tension pulling them
up
, and
m
g
mg
m
g
pulling them
down
What forces are acting upon A?
tension pulling
up
the slope
weight pulling
down
friction resisting the motion
upwards
normal reaction pushing at
right angles
to the slope
How do you resolve the weight of A into its component parts?
m
g
cos
θ
mg\cos\theta
m
g
cos
θ
m
g
sin
θ
mg\sin\theta
m
g
sin
θ
What forces are acting upon B ?
tension pulling
up
weight pulling
down
If the angle at the bottom left is
θ
\theta
θ
, what is the angle at the top right?
90
−
θ
90\ -\ \theta
90
−
θ
How do you calculate the resultant force on the pulley?
Calculate the angle at the top
right
Halve
it
Take
cos
of the result
Multiply by the
total tension
(which is
2T
)
General method for solving connected particles questions:
Do
F = ma
twice
Simultaneous equations - typically to find out what the
acceleration
and
tension
are
Typically there will be a change of state, like a string breaking. Use
SUVAT
to find out v (which will become
u
when the string breaks)
Calculate the new
acceleration
at T=0
Another
SUVAT
, use new acceleration, value of u will be
v
from before